
Concept explainers
a)
Interpretation:
The first step of the reaction shown involves the nucleophilic substitution of the S atom on the methionine side chain with BrCN to give cyanosulfonium ion [R2SCN]+. The structure of the product formed is to be given and a mechanism for its formation is to be proposed.
Concept introduction:
S atom has two unshared pair of electrons. The nucleophilic attack of an unshared pair of electron present in S on the C of BrCN will displace the bromide ion to yield cyanosulfonium ion. It is a nucleophilic substitution reaction.
To give:
The structure of the product formed in the first step of the reaction shown which involves the nucleophilic substitution of the S atom on the methionine side chain with BrCN to give cyanosulfonium ion [R2SCN]+ along with the mechanism of its formation.
b)
Interpretation:
The second step of the reaction shown is an internal SN2 reaction, in which the carbonyl oxygen of methionine residue displaces the positively charged sulfur group to form a five membered ring product. The structure of the product formed is to be given and a mechanism for its formation is to be proposed.
Concept introduction:
The internal nucleophilc attack of the unshared pair of electrons on the sulfonium ion can lead to the formation of a five membered ring product.
To give:
The structure of the product formed in the second step of the reaction shown which is an internal SN2 reaction, in which the carbonyl oxygen of methionine residue displaces the positively charged sulfur group to form a five membered ring product and a mechanism for its formation.
c)
Interpretation:
The third step of the reaction given is a hydrolysis reaction to split the peptide chain to yield a lactone. The structure of the lactone ring formed is to be given and a mechanism for its formation is to be proposed.
Concept introduction:
The imine derivative (CH=NH) when hydrolyzed with aqueous acids breaks to give a carbonyl compound and an amino derivative as products.
To give:
The structure of the lactone ring formed during the hydrolysis of the peptide chain and a mechanism for its formation.
d)
Interpretation:
The final step of the reaction given is a hydrolysis of the lactone to give the product. A mechanism for this hydrolysis reaction is to be proposed.
Concept introduction:
Lactones upon hydrolysis give hydroxy acids as products.
To propose:
A mechanism for the hydrolysis of the lactone to give the product.

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Chapter 26 Solutions
EBK ORGANIC CHEMISTRY
- Consider the reaction below and answer the following questions. Part 1 of 4 Br NaOCH2CH3 Identify the mechanisms involved. Check all that apply. SN 1 SN 2 E1 E2 None of the above Part 2 of 4 Skip Part Check esc F1 F2 lock 1 2 Q W A S #3 80 F3 F4 F5 F6 Save For © 2025 McGraw Hill LLC. All Rights Reserved. Terms ˇˇ % & 4 5 6 89 7 IK A 分 བ F7 F8 F9 F * E R T Y U 8 9 D F G H K V B N M 0 Oarrow_forwardWhat kind of holes are not generated when solid-state particles adopt a close packing pattern? Group of answer choices tetrahedral cubic octahedral None of the other choices are correctarrow_forwardFor the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. 田 Major Product: Check ☐ + I Na OH esc F1 F2 2 1 @ 2 Q W tab A caps lock S #3 80 F3 69 4 σ F4 % 95 S Click and drag to sta drawing a structure mm Save For Later 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use GO DII F5 F6 F7 F8 F9 F10 6 CO 89 & 7 LU E R T Y U 8* 9 0 D F G H J K L Z X C V B N M 36arrow_forward
- Problem 7 of 10 Draw the major product of this reaction. Ignore inorganic byproducts. S' S 1. BuLi 2. ethylene oxide (C2H4O) Select to Draw a Submitarrow_forwardFeedback (4/10) 30% Retry Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the reactant and missing intermediates involved in this reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. Incorrect, 6 attempts remaining :0: Draw the Reactant H H3CO H- HIO: Ö-CH3 CH3OH2* protonation H. a H (+) H Ο CH3OH2 O: H3C protonation CH3OH deprotonation > CH3OH nucleophilic addition H. HO 0:0 Draw Intermediate a Xarrow_forwardCan I please get the blank spaces answered/answers?arrow_forward
- 1. Identify the following alkenes as E or Z NH₂ Br 2. Draw the structures based on the IUPAC names (3R,4R)-3-bromo-4-fluoro- 1-hexene (Z)-4-bromo-2-iodo-3-ethyl- 3-heptene تر 3. For the following, predict all possible elimination product(s) and circle the major product. HO H₂SO4 Heat 80 F4 OH H2SO4 Heat 어요 F5 F6 1 A DII 4 F7 F8 F9 % & 5 6 7 * ∞ 8 BAB 3 E R T Y U 9 F D G H J K O A F11 F10arrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. ○ O 1. H₂O, pyridine 2. neutralizing work-up a N W X 人 Parrow_forward✓ Check the box under each molecule that has a total of five ẞ hydrogens. If none of the molecules fit this description, check the box underneath the table. tab OH CI 0 Br xx Br None of these molecules have a total of five ẞ hydrogens. esc Explanation Check caps lock shift 1 fn control 02 F2 W Q A N #3 S 80 F3 E $ t 01 205 % 5 F5 & 7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility FT * 8 R T Y U כ F6 9 FIG F11 F D G H J K L C X V B < N M H option command P H + F12 commandarrow_forward
- Draw the major product of this reaction. Ignore inorganic byproducts and the carboxylic acid side product. O 1. CHзMgBr (excess) 2. H₂O ✓ W X 人arrow_forwardIf cyclopentyl acetaldehyde reacts with NaOH, state the product (formula).arrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. N S S HgCl2, H2SO4 く 8 W X Parrow_forward
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