Cell Membrane Resistance The capacitance of biological membranes is about 1.0 μ F per cm 2 of membrane area, so investigators can determine the surface area of a cell membrane by using intracellular electrodes to measure the membrane’s capacitive reactance. An investigator applies a 1.0 μ A peak current at 40 kHz to a cell and measures the peak out-of-phase voltage—that is, the component of the voltage due to the capacitive reactance of the cell membrane—to be 0.16 V. If the capacitance of a cell membrane is measured to be 6.0 × 10 –11 F, what is the area? A. 6.0 × 10 –13 m 2 B. 6.0 × 10 –11 m 2 C. 6.0 × 10 –9 m 2 D. 6.0 × 10 –7 m 2
Cell Membrane Resistance The capacitance of biological membranes is about 1.0 μ F per cm 2 of membrane area, so investigators can determine the surface area of a cell membrane by using intracellular electrodes to measure the membrane’s capacitive reactance. An investigator applies a 1.0 μ A peak current at 40 kHz to a cell and measures the peak out-of-phase voltage—that is, the component of the voltage due to the capacitive reactance of the cell membrane—to be 0.16 V. If the capacitance of a cell membrane is measured to be 6.0 × 10 –11 F, what is the area? A. 6.0 × 10 –13 m 2 B. 6.0 × 10 –11 m 2 C. 6.0 × 10 –9 m 2 D. 6.0 × 10 –7 m 2
The capacitance of biological membranes is about 1.0 μF per cm2 of membrane area, so investigators can determine the surface area of a cell membrane by using intracellular electrodes to measure the membrane’s capacitive reactance. An investigator applies a 1.0 μA peak current at 40 kHz to a cell and measures the peak out-of-phase voltage—that is, the component of the voltage due to the capacitive reactance of the cell membrane—to be 0.16 V.
If the capacitance of a cell membrane is measured to be 6.0 × 10–11 F, what is the area?
3.63 • Leaping the River II. A physics professor did daredevil
stunts in his spare time. His last stunt was an attempt to jump across
a river on a motorcycle (Fig. P3.63). The takeoff ramp was inclined at
53.0°, the river was 40.0 m wide, and the far bank was 15.0 m lower
than the top of the ramp. The river itself was 100 m below the ramp.
Ignore air resistance. (a) What should his speed have been at the top of
the ramp to have just made it to the edge of the far bank? (b) If his speed
was only half the value found in part (a), where did he land?
Figure P3.63
53.0°
100 m
40.0 m→
15.0 m
Please solve and answer the question correctly please. Thank you!!
You throw a small rock straight up from the edge of a highway bridge that crosses a river. The rock passes you on its way down, 5.00 s after it was thrown. What is the speed of the rock just before it reaches the water 25.0 m below the point where the rock left your hand? Ignore air resistance.
Chapter 26 Solutions
Student Workbook for College Physics: A Strategic Approach Volume 1 (Chs. 1-16)
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