
Concept explainers
What was Andrija Mohorovičićs major contribution to Earth science?

The contribution of Andrija Mohorovičićs in Earth science.
Answer to Problem 5RQ
Andrija Mohorovičić concluded that there are different layers of Earth on the basis of the density of the rocks. He discovered the boundary of the Earth’s mantle where it is separated from the crust.
Explanation of Solution
Andrija Mohorovičićs was a meteorologist and geophysicist. He studied seismographs from a local earthquake. While studying, he realized that the seismic waves are faster as it goes deeper from the Earth's surface. The waves took speed only if there is a change in density. Therefore, he concluded that at a certain depth, Earth has a different density of rocks due to which the seismic waves become faster.
The seismograph was observed by Andrija Mohorovičić, which showed the upper boundary of Earth's mantle where there were denser rocks underlying the less dense crust. This boundary, which differentiates the mantle and the crust, is known as Mohorovičić discontinuity or "Moho." Therefore, Andrija Mohorovičić was able to discover the layers of Earth's surface.
Conclusion:
Therefore, Andrija Mohorovičić concluded that there are different layers of Earth on the basis of the density of the rocks. He discovered the boundary of the Earth’s mantle where it is separated from the crust.
Chapter 26 Solutions
Conceptual Physical Science Explorations
Additional Science Textbook Solutions
Brock Biology of Microorganisms (15th Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
Human Biology: Concepts and Current Issues (8th Edition)
Campbell Essential Biology with Physiology (5th Edition)
Microbiology: An Introduction
Applications and Investigations in Earth Science (9th Edition)
- Example Two charges, one with +10 μC of charge, and another with - 7.0 μC of charge are placed in line with each other and held at a fixed distance of 0.45 m. Where can you put a 3rd charge of +5 μC, so that the net force on the 3rd charge is zero?arrow_forward* Coulomb's Law Example Three charges are positioned as seen below. Charge 1 is +2.0 μC and charge 2 is +8.0μC, and charge 3 is - 6.0MC. What is the magnitude and the direction of the force on charge 2 due to charges 1 and 3? 93 kq92 F == 2 r13 = 0.090m 91 r12 = 0.12m 92 Coulomb's Constant: k = 8.99x10+9 Nm²/C² ✓arrow_forwardMake sure to draw a Free Body Diagram as wellarrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON





