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a)
Interpretation:
Polar head and all hydrophobic tails in sphingomyelins need to be identified and the possibility of being major constituent of lipid bilayers need to be discussed.
Concept introduction:
Lipids are a group of compounds which occur naturally and are extracted from cells using a non-polar solvent. Lipids are further classified as simple and complex lipids. The long non-polar carbon chain present in the lipid is the hydrophobic tail. The hydrophilic group or the polar group present in the lipid is known as polar head.
To identify: the polar head and all hydrophobic tails.
(b)
Interpretation:
Polar head and all hydrophobic tails in sphingomyelins need to be identified and the possibility of being major constituent of lipid bilayers need to be discussed.
Concept introduction:
Lipid bilayers are the main fabric of cell membranes. The surface of the lipid bilayer is polar where polar heads assemble. The lipid bilayers are hence water soluble. The lipid bilayers has the phosphoglyceride self-assembled. The hydrophobic tails avoid contact with the water.
To predict: whether sphingomyelins can be a major constituent of lipid bilayers.
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Chapter 26 Solutions
ORGANIC CHEMISTRY-STD.WILEY PLUS CARD
- Explanation O Conjugated Pi Systems Deducing the reactants of a Diels-Alder reaction Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Xarrow_forwardDiels Alder Cycloaddition: Focus on regiochemistry (problems E-F) –> match + of thedienophile and - of the diene while also considering stereochemistry (endo).arrow_forwardHELP! URGENT! PLEASE RESOND ASAP!arrow_forward
- Question 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 ptsarrow_forwardDetermine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267arrow_forwardDraw the products of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry. Ignore inorganic byproducts. OSO4 (cat) (CH3)3COOH Select to Draw ઘarrow_forward
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- 2. Propose a mechanism for this reaction. ہلی سے ملی N H (excess)arrow_forwardSteps and explanationn please.arrow_forwardProblem 5-48 Assign R or S configurations to the chirality centers in ascorbic acid (vitamin C). OH H OH HO CH2OH Ascorbic acid O H Problem 5-49 Assign R or S stereochemistry to the chirality centers in the following Newman projections: H Cl H CH3 H3C. OH H3C (a) H H H3C (b) CH3 H Problem 5-52 Draw the meso form of each of the following molecules, and indicate the plane of symmetry in each: OH OH (a) CH3CHCH2CH2CHCH3 CH3 H3C. -OH (c) H3C CH3 (b) Problem 5-66 Assign R or S configurations to the chiral centers in cephalexin, trade-named Keflex, the most widely prescribed antibiotic in the United States. H2N H IHH S Cephalexin N. CH3 CO₂Harrow_forward
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