Chapter 26, Problem 3P

Given

$\begin{array}{l}\frac{d{x}_1}{dt}=1999x_1+2999x_2\\ \frac{d{x}_1}{dt}=-2000x_1-3000x_2\end{array}$

If $x_1\left(0\right)=x_2\left(0\right)=1$, obtain a solution from $t=0\text{ to 0}\text{.2}$ using a step size of 0.05 with the (a) explicit and (b) implicit Euler methods.