Concept explainers
Interpretation:
5-Bromouracil causes mutations in DNA. Reason for this should be determined.
Concept introduction:
A parent DNA molecule consists of two poly
A base is nitrogen containing heterocyclic compound which is found in DNA and RNA.
There are mainly five nitrogen bases.
- (1) Adenine
- (2) Guanine
- (3) Cytosine
- (4) Thymine
- (5) Uracil
In DNA Adenine always makes a double bond with Thymine (
Enol is a tautomer which exhibiting a special type of functional isomerism namely tautomerism.
Tautomerism is a special type of functional isomerism in which isomers are in dynamic equilibrium with each other.
Mutation is the process that results in change in the sequence of the DNA, and the compound which causes mutation is known as mutagenic compound.
Trending nowThis is a popular solution!
Chapter 26 Solutions
Organic Chemistry, Books a la Carte Edition (8th Edition)
- Trehalose and maltose are both dimers of glucose. However, they have considereably different reactivities. Concisely explain why these differences are observed. но но HO HO но "HO он но он OH O HO OHOH но trehalose maltose 1. Malthose is a reducing sugar while trehalose is not. 2. Trehalose is very resistant to acid hydrolysis while maltose can be acid-hydrolyzed with ease.arrow_forwardDescribe the following sugar. OH HO- OH но OH Ketose, furanose, a Aldose, pyranose, a Ketose, furanose, B Aldose, pyranose, Barrow_forwardXylulose has the following structural formula. To what carbohydrate class does xylulose belong based on the number of carbons and carbonyl functionality? A) aldotetrose B) aldopentose C) ketotetrose D) ketopentose E) ketohexosearrow_forward
- C. Trehalose and maltose are both dimers of glucose. However, they have considereably different reactivities. Concisely explain why these differences are observed. HO НО НО HO Но HO OH Он HO OHOH Но trehalose maltose 1. Malthose is a reducing sugar while trehalose is not. 2. Trehalose is very resistant to acid hydrolysis while maltose can be acid-hydrolyzed with ease.arrow_forwardThe reaction shows the chemical synthesis of protected lactose disaccharides. Which bromide donor would you choose to accomplish this transformation? Explain your reasoning.arrow_forward4. An iterative approach to oligosaccharide synthesis involves the use of protected glycals (sugars with C1-C2 double bond) as shown below. The product from the reaction of the first glycal with DMDO under anhydrous conditions is treated with another suitably-protected glycal to form a disaccharide glycal, and the process can be repeated to form a trisaccharide glycal, and so on... Crucial to the success of this approach is the stereoselective formation of the intermediate A in the scheme below. Draw the structure of A. DMDO CH₂Cl2 A OH ZnCl₂, THF OHarrow_forward
- Crocin, which occurs naturally in crocus and gardenia owers, is primarily responsible for the color of saffron. (a) What lipid and monosaccharides are formed by the hydrolysis of crocin? (b) Classify the lipid as a monoterpenoid, diperpenoid, etc., and locate the isoprene units.arrow_forwardIn glycoside formation, the hemiacetal functional group of a cyclic monosaccharide is converted to an acetal group by reaction with a(an)arrow_forwardIn much the same way that aldoses are reduced with H 2 and Pd, 2-ketohexoses are also reduced. One difference occurs, however, in that two products are formed on reduction of 2-ketohexoses. Draw the two products formed when fructose (Section 20.2C) is reduced, and label the products as stereoisomers, constitutional isomers, or anomers. Explain your choice.arrow_forward
- Ribose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in principle, could contain either a four-membered, five-membered, or six-membered ring. To determine which ring is formed, ribose is treated with methanol in the presence of an acid catalyst. The products are then isolated and treated with NaIO4 then with H30*. OH Меон 1. NalO4 2. H30* A & B MEOH + products HO H. H* isomeric cyclic acetals with formula CgH1205 ÕH ÕH Ribose, C5H1005 Assuming that ribose formed a six-membered ring cyclic hemiacetal, draw the structure of compounds A and B.arrow_forwardHumans are able to digest amylose, but not cellulose. What structural features of these polysaccharides might be responsible for this? O amylose contains only beta glycosidic bonds where cellulose contains alpha glycosidic bonds O amylose contains only beta glycosidic bonds where cellulose contains alpha glycosidic bonds amylose contains only alpha peptide bonds where cellulose contains beta peptide bonds amylose contains only alpha glycosidic bonds where cellulose contains beta glycosidic bondsarrow_forwardSugar alcohols (alditols) are formed by chemically reducing aldoses or ketoses. Which one of the following sugars will give a negative Benedict's Test? aldopentoses alditols 2- Ketopentoses an aldose undergoing mutarotation in solutionarrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning