
Concept explainers
(a)
The distance of the image of car that is following the person.
(a)

Answer to Problem 22P
The image of the car is at
Explanation of Solution
Given info: The height of the following car is
The rear view mirror is flat plane mirror and for the case of plane mirror the object distance is same as the image distance. Therefore the image distance for the following car is same as the car itself.
Hence, the distance of the car from observer eyes as seen through the flat rear view side mirror is,
Here,
Substitute
Conclusion:
Therefore, the image of the car form the observer’s eye is at distance of
(b)
The angle subtended by the image for the observer.
(b)

Answer to Problem 22P
The angle subtended is
Explanation of Solution
Given info: The height of the following car is
Formula to calculate the angle subtended by the object,
Here,
For the case of plane mirrors the object height and image height are equal and object distance and image distance are equal. Hence, to find the angle subtended by the image of the following car
Substitute
Conclusion:
Therefore, the angle subtended is
(c)
The image distance from the observers eye if the rear view mirror is a convex mirror.
(c)

Answer to Problem 22P
The image is at
Explanation of Solution
Given info: The height of the following car is
Formula to calculate the image distance form a convex mirror for a given object is
Here,
Substitute
Negative
The image distance is negative because the image is formed behind the mirror. Therefore the image distance from the observer’s eye is,
Here,
Substitute
Conclusion:
Therefore, the image of the following car is at
(d)
The angle subtended in the image of view for the observer in the case of convex rear view mirror.
(d)

Answer to Problem 22P
The angle subtended is
Explanation of Solution
Given info: The height of the following car is
From Equation (2) formula to calculate the angle subtended by the image,
Here,
For the case of convex mirrors the object height and image height are not equal.
Formula to calculate the image height is,
Here,
Substitute
From equation (6) and equation (9) respectively, substitute
Conclusion:
Therefore, the angle subtended is
(e)
The distance of the following car based on the angle subtended by the image in the observers eye.
(e)

Answer to Problem 22P
The distance of the following car based on the angular spread in the human eye is
Explanation of Solution
Given info: The height of the following car is
Formula to calculate the angle subtended by the image,
Here,
Substitute
Conclusion:
Therefore, the image appears to be
Want to see more full solutions like this?
Chapter 26 Solutions
Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)
- In the comics Thor flies by spinning his hammer really fast from a leather strap at the end of the handle, letting go, then grabbing it and having it pull him. If Thor wants to reach escape velocity (velocity needed to leave Earth’s atmosphere), he will need the linear velocity of the center of mass of the hammer to be 11,200 m/s. A) If the distance from the end of the strap to the center of the hammer is 0.334 m, what angular velocity does Thor need to spin his hammer at to reach escape velocity? b) If the hammer starts from rest what angular acceleration does Thor need to reach that angular velocity in 4.16 s? c) While the hammer is spinning at its maximum speed what impossibly large tension does the leather strap, which the hammer is spinning by, exert when the hammer is at its lowest point? The hammer has a total mass of 20.0kg.arrow_forwardThe car goes from driving straight to spinning at 10.6 rev/min in 0.257 s with a radius of 12.2 m. The angular accleration is 4.28 rad/s^2. During this flip Barbie stays firmly seated in the car’s seat. Barbie has a mass of 58.0 kg, what is her normal force at the top of the loop?arrow_forwardConsider a hoop of radius R and mass M rolling without slipping. Which form of kinetic energy is larger, translational or rotational?arrow_forward
- A roller-coaster vehicle has a mass of 571 kg when fully loaded with passengers (see figure). A) If the vehicle has a speed of 22.5 m/s at point A, what is the force of the track on the vehicle at this point? B) What is the maximum speed the vehicle can have at point B, in order for gravity to hold it on the track?arrow_forwardThis one wheeled motorcycle’s wheel maximum angular velocity was about 430 rev/min. Given that it’s radius was 0.920 m, what was the largest linear velocity of the monowheel?The monowheel could not accelerate fast or the rider would start spinning inside (this is called "gerbiling"). The maximum angular acceleration was 10.9 rad/s2. How long, in seconds, would it take it to hit maximum speed from rest?arrow_forwardIf points a and b are connected by a wire with negligible resistance, find the magnitude of the current in the 12.0 V battery.arrow_forward
- Consider the two pucks shown in the figure. As they move towards each other, the momentum of each puck is equal in magnitude and opposite in direction. Given that v kinetic energy of the system is converted to internal energy? 30.0° 130.0 = green 11.0 m/s, and m blue is 25.0% greater than m 'green' what are the final speeds of each puck (in m/s), if 1½-½ t thearrow_forwardConsider the blocks on the curved ramp as seen in the figure. The blocks have masses m₁ = 2.00 kg and m₂ = 3.60 kg, and are initially at rest. The blocks are allowed to slide down the ramp and they then undergo a head-on, elastic collision on the flat portion. Determine the heights (in m) to which m₁ and m2 rise on the curved portion of the ramp after the collision. Assume the ramp is frictionless, and h 4.40 m. m2 = m₁ m hm1 hm2 m iarrow_forwardA 3.04-kg steel ball strikes a massive wall at 10.0 m/s at an angle of 0 = 60.0° with the plane of the wall. It bounces off the wall with the same speed and angle (see the figure below). If the ball is in contact with the wall for 0.234 s, what is the average force exerted by the wall on the ball? magnitude direction ---Select--- ✓ N xarrow_forward
- You are in the early stages of an internship at NASA. Your supervisor has asked you to analyze emergency procedures for extravehicular activity (EVA), when the astronauts leave the International Space Station (ISS) to do repairs to its exterior or perform other tasks. In particular, the scenario you are studying is a failure of the manned-maneuvering unit (MMU), which is a nitrogen-propelled backpack that attaches to the astronaut's primary life support system (PLSS). In this scenario, the astronaut is floating directly away from the ISS and cannot use the failed MMU to get back. Therefore, the emergency plan is to take off the MMU and throw it in a direction directly away from the ISS, an action that will hopefully cause the astronaut to reverse direction and float back to the station. You have the following mass data provided to you: astronaut: 78.1 kg, spacesuit: 36.8 kg, MMU: 115 kg, PLSS: 145 kg. Based on tests performed by astronauts floating "weightless" inside the ISS, the most…arrow_forwardThree carts of masses m₁ = 4.50 kg, m₂ = 10.50 kg, and m3 = 3.00 kg move on a frictionless, horizontal track with speeds of V1 v1 13 m 12 mq m3 (a) Find the final velocity of the train of three carts. magnitude direction m/s |---Select--- ☑ (b) Does your answer require that all the carts collide and stick together at the same moment? ○ Yes Ο Νο = 6.00 m/s to the right, v₂ = 3.00 m/s to the right, and V3 = 6.00 m/s to the left, as shown below. Velcro couplers make the carts stick together after colliding.arrow_forwardA girl launches a toy rocket from the ground. The engine experiences an average thrust of 5.26 N. The mass of the engine plus fuel before liftoff is 25.4 g, which includes fuel mass of 12.7 g. The engine fires for a total of 1.90 s. (Assume all the fuel is consumed.) (a) Calculate the average exhaust speed of the engine (in m/s). m/s (b) This engine is positioned in a rocket body of mass 70.0 g. What is the magnitude of the final velocity of the rocket (in m/s) if it were to be fired from rest in outer space with the same amount of fuel? Assume the fuel burns at a constant rate. m/sarrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningUniversity Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning





