EBK BIOCHEMISTRY
EBK BIOCHEMISTRY
6th Edition
ISBN: 9781337431200
Author: GRISHAM
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Chapter 26, Problem 1P
Interpretation Introduction

Interpretation:

The purine and pyrimidine ring structures should be drawn demonstrating the metabolic sources of all the atoms in the ring.

Concept Introduction:

Heterocyclic aromatic organic compound purine has a pyrimidine ring fused to an imidazole ring. Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms, whereas pyrimidine is a six-membered single ring structure.

Expert Solution & Answer
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Explanation of Solution

Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms. In this structure, carbon-2 and carbon-8 are obtained from N10 -formyl −H4folate and nitrogen-3 and nitrogen-9 are obtained from glutamine. There is no metabolic relation between purine and pyrimidines. Purine and Pyrimidines both have a different process for the synthesis and for the degradation. These both process of degradation and synthesis occur in all organisms. Structure of the purine is given below-

  EBK BIOCHEMISTRY, Chapter 26, Problem 1P , additional homework tip  1

Pyrimidine is a six-membered single ring structure. It has two nitrogen and four carbon atoms. Nitrogen-3 and carbon-2 are obtained from carbamoyl phosphate. Carbon-4,5,6 and nitrogen-1 are obtained from aspartate. Structure for the pyrimidine is given below-

  EBK BIOCHEMISTRY, Chapter 26, Problem 1P , additional homework tip  2

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