Tutorials in Introductory Physics
1st Edition
ISBN: 9780130970695
Author: Peter S. Shaffer, Lillian C. McDermott
Publisher: Addison Wesley
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Question
Chapter 25.7, Problem 1bTH
To determine
The ranking of intensity of light after passing through the second polarizer in each case when the incident light is vertically polarised.
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Students have asked these similar questions
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SARET CRKS AUTOWAY
12. A stone is dropped from the top of a cliff. It is seen to hit the ground below
after 3.55 s. How high is the cliff?
13. A ball is dropped from rest at the top of a building that is 320 m tall. Assuming
no air resistance, what is the speed of the ball just before it strikes the ground?
14. Estimate (a) how long it took King Kong to fall straight down from the top
of the Empire State Building (280m high), and (b) his velocity just before
"landing".
Useful equations
For Constant Velocity:
V =>
D
X = V₁t + Xo
For Constant Acceleration:
Vr = V + at
X = Xo+Vot +
v=V+2a(X-Xo)
\prom = V +V
V velocity
t = time
D Distance
X = Final Position
Xo Initial Position
V = Final Velocity
Vo Initial Velocity
a = acceleration
For free fall
Yf
= Final Position
Yo Initial Position
g = 9.80
m
$2
For free fall:
V = V + gt
Y=Yo+Vo t +
+gt
V,² = V₁²+2g (Y-Yo)
V+Vo
Vprom=
2
6
Solve the problems
Chapter 25 Solutions
Tutorials in Introductory Physics
Ch. 25.1 - The top view diagram at right illustrates two...Ch. 25.1 - The top view diagram at right illustrates two...Ch. 25.1 - Label each nodal line and line of maximum...Ch. 25.1 - Prob. 2bTHCh. 25.1 - How do the angles a and ß compare? Explain.Ch. 25.1 - Prob. 3bTHCh. 25.1 - Prob. 3cTHCh. 25.1 - The enlarged diagram at right illustrates the...Ch. 25.1 - For what values of D (in terms of ) will there be:...Ch. 25.1 - Use your answers from parts d and e to write...
Ch. 25.1 - Determine the angles for which there will be nodal...Ch. 25.1 - Consider the following incorrect statement...Ch. 25.2 - In the space above the photograph at right,...Ch. 25.2 - The screen is 2.2m from the slits, and the...Ch. 25.2 - Suppose that the width of the right slit were...Ch. 25.2 - The graph of intensity versus angle at right...Ch. 25.3 - The photograph at right illustrates the pattern...Ch. 25.3 - The photograph at right illustrates the pattern...Ch. 25.3 - Consider the original doubleslit pattern from...Ch. 25.3 - Consider the original doubleslit pattern from...Ch. 25.3 - Consider the original doubleslit pattern from...Ch. 25.3 - Prob. 3aTHCh. 25.3 - Monochromatic light from a distant point source...Ch. 25.4 - Light from a distant point source is incident on a...Ch. 25.4 - The graph at right shows the intensity on a...Ch. 25.4 - The graph at right shows the intensity on a...Ch. 25.4 - There is a systematic way of determining the...Ch. 25.4 - There is a systematic way of determining the...Ch. 25.4 - There is a systematic way of determining the...Ch. 25.5 - Monochromatic light from a distant point source is...Ch. 25.5 - Monochromatic light from a distant point source is...Ch. 25.5 - Light from a laser (=633nm) is incident on two...Ch. 25.5 - Monochromatic light from a distant point source is...Ch. 25.5 - Monochromatic light from a distant point source is...Ch. 25.5 - Monochromatic light from a distant point source is...Ch. 25.6 - Recall the situation from tutorial, in which light...Ch. 25.6 - Recall the situation from tutorial, in which light...Ch. 25.6 - A plate of glass (n=1.5) is placed over a flat...Ch. 25.6 - A plate of glass (n=1.5) is placed over a flat...Ch. 25.6 - A plate of glass (n=1.5) is placed over a flat...Ch. 25.7 - Identical beams of light are incident on three...Ch. 25.7 - Prob. 1bTHCh. 25.7 - Unpolarized light of intensity I0 incident on a...Ch. 25.7 - Unpolarized light of intensity I0 incident on a...Ch. 25.7 - Unpolarized light of intensity I0 incident on a...Ch. 25.7 - Unpolarized light of intensity I0 incident on a...Ch. 25.7 - Unpolarized red light is incident on two...Ch. 25.7 - Unpolarized red light is incident on two...Ch. 25.7 - Unpolarized red light is incident on two...Ch. 25.7 - Unpolarized red light is incident on two...
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