(a) Explanation Given info: A battery voltage is measured using voltmeter with internal resistance 10.00 k Ω and the result is 4.982 V and a 15.00 k Ω meter gives 4.993 V . Explanation: The resistance of the battery R 1 and the internal resistance of voltmeter R int is in series, hence the total resistance will be the sum of both. Write the expression for the current I = ε R 1 + R int (1) Here, I is the current ε is the voltage of the battery R 1 is the resistance of the battery R int is the internal resistance of the voltmeter Write the expression for voltage drop across the voltmeter V m = I R int (2) Substitute equation (1) in (2) V m = ε R 1 + R int R int (3) Here, V m is the measured voltage Substitute 4.982 V for V m and 15.00 k Ω for R int in equation (3) for first voltmeter 4.982 V = ε ( 10.00 k Ω ) R + 10.00 k Ω (4) Rearrange equation (4) R 1 + 10 (b) To determine The internal resistance of battery.

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ISBN: 9780134988566

Author: Wolfson, Richard

Publisher: Pearson Education,

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Temperature Variance of Resistance

Electrical resistance or simply resistance is the property of a material that opposes the free flow of electrons through it. The total amount of resistance to the flow of charges (or current) is affected by many factors like the length of the conducting …

Question

Chapter 25, Problem 63P

(a)

To determine

The voltage of the battery.

(b)

To determine

The internal resistance of battery.

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Chapter 25, Problem 62P

Chapter 25, Problem 64P

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Chapter 25 Solutions

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The voltage of the battery.

Solution Summary: The author explains that the battery voltage is measured using a voltmeter with internal resistance 10.00kOmega and the total resistance is the sum of both.

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The voltage of the battery.

The internal resistance of battery.

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Chapter 25 Solutions