Explanation Given: The limit function is lim x → 27 x − 27 x 1 3 − 3 . Formula used: The identity is: a 3 − b 3 = ( a − b ) ( a 2 + a b + b 2 ) Calculation: The limit function is lim x → 27 x − 27 x 1 3 − 3 . We can rewrite it as: lim x → 27 x − 27 x 1 3 − 3 = lim x → 27 ( x 1 3 ) 3 − 3 3 x 1 3 − 3 Now, find the limit. First, transform algebraically the function. Use the identity in the numerator. ( x 1 3 ) 3 − 3 3 = ( x 1 3 − 3 ) ( x 2 3 + 3 x 1 3 + 9 ) Substitute the factors in the function

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Percentage

A percentage is a number indicated as a fraction of 100. It is a dimensionless number often expressed using the symbol %.

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In mathematics, an algebraic expression consists of constant(s), variable(s), and mathematical operators. It is made up of terms.

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Numbers are some measures used for counting. They can be compared one with another to know its position in the number line and determine which one is greater or lesser than the other.

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Question

Chapter 2.5, Problem 46E

To determine

Evaluate the function by using the identity a3−b3=(a−b)(a2+ab+b2).

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Chapter 2.5, Problem 45E

Chapter 2.5, Problem 47E

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Consider the graphs of y = f(x) and y = g(x) in the given diagram y= f(x). y = g(x) Evaluate (f+g)(2) -5 Determine all for which g(x) < f(x) Determine all for which f(x) +3 = g(x)

I) For what value(s) of x does g(x) = -4? Separate multiple answers with commas as needed. J) Give the interval(s) of such that g(x) > 0. Use the union symbol between multiple intervals. K) Give the interval(s) of such that g(x) <0. Use the union symbol between multiple intervals.

need help on B

Chapter 2 Solutions

CALCULUS (CLOTH)

Ch. 2.1 - Prob. 1PQ Ch. 2.1 - Prob. 2PQ Ch. 2.1 - Prob. 3PQ Ch. 2.1 - Prob. 4PQ Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E

Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.2 - Prob. 1PQ Ch. 2.2 - Prob. 2PQ Ch. 2.2 - Prob. 3PQ Ch. 2.2 - Prob. 4PQ Ch. 2.2 - Prob. 5PQ Ch. 2.2 - Prob. 6PQ Ch. 2.2 - Prob. 7PQ Ch. 2.2 - Prob. 1E Ch. 2.2 - Prob. 2E Ch. 2.2 - Prob. 3E Ch. 2.2 - Prob. 4E Ch. 2.2 - Prob. 5E Ch. 2.2 - Prob. 6E Ch. 2.2 - Prob. 7E Ch. 2.2 - Prob. 8E Ch. 2.2 - Prob. 9E Ch. 2.2 - Prob. 10E Ch. 2.2 - Prob. 11E Ch. 2.2 - Prob. 12E Ch. 2.2 - Prob. 13E Ch. 2.2 - Prob. 14E Ch. 2.2 - Prob. 15E Ch. 2.2 - Prob. 16E Ch. 2.2 - Prob. 17E Ch. 2.2 - Prob. 18E Ch. 2.2 - Prob. 19E Ch. 2.2 - 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Evaluate the function by using the identity a 3 − b 3 = ( a − b ) ( a 2 + a b + b 2 ) .

Solution Summary: The author explains that the limit function is undersetxto 27mathrmlim

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Evaluate the function by using the identity a3−b3=(a−b)(a2+ab+b2).

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Chapter 2 Solutions