Concept explainers
(a)
Interpretation: The formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving a
Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.
(b)
Interpretation: The reasons as to why
Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.
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Organic Chemistry (6th Edition)
- The alkene shown undergoes bromination. (a) Draw the product(s) of bromination of this compound, including all expected stereoisomers (if any). Use wedge‑and‑dash bonds to designate the stereochemistry at any chirality centers, and make sure to draw an explicit hydrogen if a chirality center has one. (b) Characterize the starting alkene as having the E or Z configuration. (c) characterize the product(s).arrow_forwardThe bicyclic heterocycles quinoline and indole undergo electrophilic aromatic substitution to give the products shown. (a) Explain why electrophilic substitution occurs on the ring without the N atom for quinoline, but occurs on the ring with the N atom in indole. (b) Explain why electrophilic substitution occurs more readily at C8 than C7 in quinoline. (c) Explain why electrophilic substitution occurs more readily at C3 rather than C2 of indole.arrow_forwardWhen treated with NaOH, the bromide below gives an alkene by the E2 mechanism, by elimination of the H atom indicated by the arrow: (a) Draw the Newman projection from which elimination takes place. (b) Draw the mechanism. (c) Draw the product with the proper stereochemistry. (d) Assign the proper stereochemical descriptor to the product. (e) Give the rate equationarrow_forward
- The spirocyclic pentadiene derivative F shown below is converted stereospecificallyinto compound G on heating. The transformation involves two consecutive pericyclicreactions of the same type, and proceeds via compound H which is not isolated. Identify the type of pericyclic reaction occurring, and determine the structure ofcompound H.arrow_forward6arrow_forwardWhen buta-1,3-diene (CH2 = CH – CH = CH2) is treated with HBr, two constitutional isomers are formed, CH3CHBrCH = CH2 and BrCH2CH = CHCH3. Draw a stepwise mechanism that accounts for the formation of both products.arrow_forward
- Elimination occurs when (Z)-3-bromohex-3-ene is treated with NaNH2. Under the same conditions, 1-bromocyclohexeneundergoes elimination much more sluggishly. Explain whyarrow_forwardWhen (CH3)3C-C=C-H is treated with HCI, (CH3)2C(CI)C(CH3)C=CH₂ is formed as a minor product. Suggest a mechanism that would account for this transformation.arrow_forward(a) What product is formed when triene N undergoes thermal electrocyclic ring closure? (b) What product is formed when triene N undergoes photochemical ring closure? (c) Label each process as conrotatory or disrotatory.arrow_forward
- From trans-1-chloro-2-isopropylcyclohexane, only 3-isopropylcyclohexene, the less substituted alkene, is formed. Using conformational analysis, explain why this product is observed. Also, will the E2 reaction with trans-1-chloro- 2-isopropylcyclohexane or cis-1-chloro-2-isopropylcyclohexane occur faster under the same basic conditions? CH;O Na* CH3OH CI trans-1-Chloro-2 (R)-3-Isopropylcyclohexene isopropylcyclohexanearrow_forwardPara-substituted product was produced when phenol reacts with cyclohexanecarbonyl bromide in the presence of AIB13. -Br Cyclohexanecarbonyl bromide (i) Outline the mechanism for this reaction. (ii) Draw the alternative substituted product formed.arrow_forward| Anthracene readily undergoes a Diels-Alder reaction with tetracyanoethene, even though anthracene is NC CN ? + aromatic. NC CN (a) Draw two possible products that can form from this reaction. (b) Explain why anthracene can readily undergo a Diels-Alder reaction, whereas benzene does not.arrow_forward