(a) Interpretation: The nuclides naturally more stable in between N 10 20 e a n d N 10 22 e is to be determined. Concept introduction: The balance between protons and neutrons in a nucleus determine the nucleus will be stable or not. The element of smaller atomic numbers should have the same number of protons and neutrons in accordance to make a nucleus stable.

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Answer 1

Question

Chapter 25, Problem 41E

Interpretation Introduction

(a)

Interpretation:

The nuclides naturally more stable in between N1020eandN1022e is to be determined.

Concept introduction:

The balance between protons and neutrons in a nucleus determine the nucleus will be stable or not. The element of smaller atomic numbers should have the same number of protons and neutrons in accordance to make a nucleus stable.

Interpretation Introduction

(b)

Interpretation:

The nuclides naturally more stable in between O817andO818 is to be determined.

Concept introduction:

Unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. So, the number of these two should be the same in elements having smaller atomic numbers.

Interpretation Introduction

(c)

Interpretation:

The nuclides naturally more stable in between L36iandL37i is to be determined.

Concept introduction:

Normally, in naturally occurring elements unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. In side nucleus, if a number of proton and neutrons both are in odd numbers this atom is naturally unstable.

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Answer 2

Question

Chapter 25, Problem 41E

Interpretation Introduction

(a)

Interpretation:

The nuclides naturally more stable in between N1020eandN1022e is to be determined.

Concept introduction:

The balance between protons and neutrons in a nucleus determine the nucleus will be stable or not. The element of smaller atomic numbers should have the same number of protons and neutrons in accordance to make a nucleus stable.

Interpretation Introduction

(b)

Interpretation:

The nuclides naturally more stable in between O817andO818 is to be determined.

Concept introduction:

Unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. So, the number of these two should be the same in elements having smaller atomic numbers.

Interpretation Introduction

(c)

Interpretation:

The nuclides naturally more stable in between L36iandL37i is to be determined.

Concept introduction:

Normally, in naturally occurring elements unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. In side nucleus, if a number of proton and neutrons both are in odd numbers this atom is naturally unstable.

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Answer 3

Question

Chapter 25, Problem 41E

Interpretation Introduction

(a)

Interpretation:

The nuclides naturally more stable in between N1020eandN1022e is to be determined.

Concept introduction:

The balance between protons and neutrons in a nucleus determine the nucleus will be stable or not. The element of smaller atomic numbers should have the same number of protons and neutrons in accordance to make a nucleus stable.

Interpretation Introduction

(b)

Interpretation:

The nuclides naturally more stable in between O817andO818 is to be determined.

Concept introduction:

Unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. So, the number of these two should be the same in elements having smaller atomic numbers.

Interpretation Introduction

(c)

Interpretation:

The nuclides naturally more stable in between L36iandL37i is to be determined.

Concept introduction:

Normally, in naturally occurring elements unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. In side nucleus, if a number of proton and neutrons both are in odd numbers this atom is naturally unstable.

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Answer 4

Question

Chapter 25, Problem 41E

Interpretation Introduction

(a)

Interpretation:

The nuclides naturally more stable in between N1020eandN1022e is to be determined.

Concept introduction:

The balance between protons and neutrons in a nucleus determine the nucleus will be stable or not. The element of smaller atomic numbers should have the same number of protons and neutrons in accordance to make a nucleus stable.

Interpretation Introduction

(b)

Interpretation:

The nuclides naturally more stable in between O817andO818 is to be determined.

Concept introduction:

Unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. So, the number of these two should be the same in elements having smaller atomic numbers.

Interpretation Introduction

(c)

Interpretation:

The nuclides naturally more stable in between L36iandL37i is to be determined.

Concept introduction:

Normally, in naturally occurring elements unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. In side nucleus, if a number of proton and neutrons both are in odd numbers this atom is naturally unstable.

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Answer 5

Chapter 25, Problem 41E

Interpretation Introduction

(a)

Interpretation:

The nuclides naturally more stable in between N1020eandN1022e is to be determined.

Concept introduction:

The balance between protons and neutrons in a nucleus determine the nucleus will be stable or not. The element of smaller atomic numbers should have the same number of protons and neutrons in accordance to make a nucleus stable.

Interpretation Introduction

(b)

Interpretation:

The nuclides naturally more stable in between O817andO818 is to be determined.

Concept introduction:

Unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. So, the number of these two should be the same in elements having smaller atomic numbers.

Interpretation Introduction

(c)

Interpretation:

The nuclides naturally more stable in between L36iandL37i is to be determined.

Concept introduction:

Normally, in naturally occurring elements unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. In side nucleus, if a number of proton and neutrons both are in odd numbers this atom is naturally unstable.

Answer 6

Chapter 25, Problem 41E

Interpretation Introduction

(a)

Interpretation:

The nuclides naturally more stable in between N1020eandN1022e is to be determined.

Concept introduction:

The balance between protons and neutrons in a nucleus determine the nucleus will be stable or not. The element of smaller atomic numbers should have the same number of protons and neutrons in accordance to make a nucleus stable.

Answer 7

Chapter 25, Problem 41E

Interpretation Introduction

(a)

Interpretation:

The nuclides naturally more stable in between N1020eandN1022e is to be determined.

Concept introduction:

The balance between protons and neutrons in a nucleus determine the nucleus will be stable or not. The element of smaller atomic numbers should have the same number of protons and neutrons in accordance to make a nucleus stable.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The nuclides naturally more stable in between O817andO818 is to be determined.

Concept introduction:

Unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. So, the number of these two should be the same in elements having smaller atomic numbers.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The nuclides naturally more stable in between O817andO818 is to be determined.

Concept introduction:

Unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. So, the number of these two should be the same in elements having smaller atomic numbers.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The nuclides naturally more stable in between L36iandL37i is to be determined.

Concept introduction:

Normally, in naturally occurring elements unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. In side nucleus, if a number of proton and neutrons both are in odd numbers this atom is naturally unstable.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The nuclides naturally more stable in between L36iandL37i is to be determined.

Concept introduction:

Normally, in naturally occurring elements unequal numerical distribution of proton and neutron in the nucleus leads to nuclear instability. In side nucleus, if a number of proton and neutrons both are in odd numbers this atom is naturally unstable.

Answer 12

Expert Solution & Answer

Answer 13

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Answer 14

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Answer 15

Ch. 25 - Prob. 1E Ch. 25 - Prob. 2E Ch. 25 - Prob. 3E Ch. 25 - Prob. 4E Ch. 25 - Prob. 5E Ch. 25 - Prob. 6E Ch. 25 - Prob. 7E Ch. 25 - Prob. 8E Ch. 25 - Prob. 9E Ch. 25 - Prob. 10E

Solution Summary: The author explains that the balance between protons and neutrons in a nucleus determines whether it will be stable or not.

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Chapter 25 Solutions