The monosaccharide units present in stachyose has to be named and whether they are D-monosaccharides or L-monosaccharides has to be specified. Concept-Introduction: The D- and L-forms of monosaccharides are given as when the monosaccharide structure is written in Fischer projection form, if the –OH group at the penultimate carbon is located on right side, it is said to be D-monosaccharide and if the –OH group is on left side, it is said to be L-monosaccharide.

Question

You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: xi 1. ☑ 2. H₂O хе i Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. There is no reagent that will make this synthesis work without complications. : ☐ S ☐

Answer 1

Question

Chapter 25, Problem 25.39P

(a)

Interpretation Introduction

Interpretation:

The monosaccharide units present in stachyose has to be named and whether they are D-monosaccharides or L-monosaccharides has to be specified.

Concept-Introduction:

The D- and L-forms of monosaccharides are given as when the monosaccharide structure is written in Fischer projection form, if the –OH group at the penultimate carbon is located on right side, it is said to be D-monosaccharide and if the –OH group is on left side, it is said to be L-monosaccharide.

(b)

Interpretation Introduction

Interpretation:

The glycosidic bond present in the stachyose molecule has to be identified.

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