Three plausible termination steps for the reaction in Equation 25-32 are to be drawn. Concept introduction: A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H + adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide ( RO-OR ) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C , and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

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Chapter 25, Problem 25.21YT

Interpretation Introduction

Interpretation:

Three plausible termination steps for the reaction in Equation 25-32 are to be drawn.

Concept introduction:

A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H+ adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide (RO-OR) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C, and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

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