Interpretation:
A termination step for the reaction in Equation 25-17 that is different from the ones shown in Equation 25-20 is to be drawn.
Concept introduction:
Halogen molecules undergo homolysis when irradiated with UV light to produce two radical atoms. Homolysis is the type of bond dissociation where each atom gets one of the bond electrons. An unpaired electron present in radical of atom or molecule. It is highly unstable, and therefore a highly reactive species. This homolytic dissociation is called initiation.
Being reactive, a radical will react with other species present. This produces another radical, which can continue the reaction is a step called propagation. The reaction is generally branched as each initiation step produces two radicals. The propagation steps carry on as long as radicals are present, and may be completed by a reaction between any two radicals.

Want to see the full answer?
Check out a sample textbook solution
Chapter 25 Solutions
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
- Draw the product of the reaction shown below. Ignore small byproducts that would evaporate pleasearrow_forwardPoly(ethylene adipate) is a biodegradable polyester (shown below). Identify the type of polymerization process used in the production of this polymer.arrow_forwardPolymers may be composed of thousands of monomers. draw two repeat units(dimer) of the polymer formed in this reaction. assume there are hydrogen atoms on the two ends of the dimer. ignore inorganic byproducts pleasearrow_forward
- Draw the product of the reaction shown below. Use a dash or wedge bond to indicate stereochemistry of substituents on asymmetric centers, Ignore inorganic byproductsarrow_forwardDraw the product of this reaction please. Ignore inorganic byproductsarrow_forwardOne of the pi molecular orbitals of 1,3-butadiene (CH2=CHCH=CH2) is shown below. Please identify the number of nodal planes perpendicular to the bonding axisarrow_forward
- Draw the monomers required to synthesize this condensation polymer please.arrow_forwardProvide the correct systematic name for the compound shown here. Please take into account the keyboard options belowarrow_forwardcurved arrows are used to illustrate the flow of electrons. using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s)arrow_forward
- Identify the 'cartoon' drawing of the acceptor orbital in the first mechanistic step of an electrophilic addition reaction of butadiene with HBr. Pleasearrow_forwardH- H H H H H H Identify and select all structures below that represent a constitutional isomer(s) of the compound shown above. H- H H H A. H H H H-C CI H H D. H H H H H H C C -H H C C H H H H B. H CI H H- C C H H H H E. H CI H C.arrow_forwardWhy doesn't this carry on to form a ring by deprotonating the alpha carbon and the negatively-charged carbon attacking the C=O?arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





