Organic Chemistry Study Guide and Solutions
Organic Chemistry Study Guide and Solutions
6th Edition
ISBN: 9781936221868
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 25, Problem 25.1P
Interpretation Introduction

(a)

Interpretation:

The structure for each of the given thioesters.

Concept Introduction:

Thioesters are sulfur analogs of esters. The S-alkyl or S-aryl thioester has a carbonyl group and a sulfur-linked alkyl or aryl group. The first part of the name indicates that the alkyl or aryl group has bonded to the sulfur atom. The last part of the name indicates the carboxylic acid stem. In common usage, the “S-“prefix is understood, and so, it is not mentioned.

Expert Solution
Check Mark

Answer to Problem 25.1P

Organic Chemistry Study Guide and Solutions, Chapter 25, Problem 25.1P , additional homework tip  1

Explanation of Solution

In the given name cyclohexyl thiobenzoate, the cyclohexyl is the alkyl group which is bonded to the sulfur atom. Thiobenzoate consists of a phenyl ring bonded to the sulfur atom through a carbonyl group. The structure for cyclohexyl thiobenzoate is drawn as below:

Organic Chemistry Study Guide and Solutions, Chapter 25, Problem 25.1P , additional homework tip  2

Conclusion

The structure for cyclohexyl thiobenzoate is:

Organic Chemistry Study Guide and Solutions, Chapter 25, Problem 25.1P , additional homework tip  3

Interpretation Introduction

(b)

Interpretation:

The structure for each of the given thioesters.

Concept Introduction:

Thioesters are sulfur analogs of esters. The S-alkyl or S-aryl thioester has a carbonyl group and a sulfur-linked alkyl or aryl group. The first part of the name indicates that the alkyl or aryl group has bonded to the sulfur atom. The last part of the name indicates the carboxylic acid stem. In common usage, the “S-“prefix is understood, and so, it is not mentioned.

Expert Solution
Check Mark

Answer to Problem 25.1P

Organic Chemistry Study Guide and Solutions, Chapter 25, Problem 25.1P , additional homework tip  4

Explanation of Solution

The first part of the name suggests that the isopropyl group must be attached directly to the sulfur atom. The second part of the name suggests that the ester is formed from butanoic acid. In IUPAC nomenclature, “thio-“is inserted before the “ate” suffix in the name of the corresponding oxygen ester. The structure for S-isopropyl butanethioate is shown as below:

Organic Chemistry Study Guide and Solutions, Chapter 25, Problem 25.1P , additional homework tip  5

Conclusion

The structure for S-isopropyl butanethioate is:

Organic Chemistry Study Guide and Solutions, Chapter 25, Problem 25.1P , additional homework tip  6

Interpretation Introduction

(c)

Interpretation:

The structure for each of the given thioesters.

Concept Introduction:

Thioesters are sulfur analogs of esters. The S-alkyl or S-aryl thioester has a carbonyl group and a sulfur-linked alkyl or aryl group. The first part of the name indicates that the alkyl or aryl group has bonded to the sulfur atom. The last part of the name indicates the carboxylic acid stem. In common usage, the “S-“prefix is understood, and so, it is not mentioned.

Expert Solution
Check Mark

Answer to Problem 25.1P

Organic Chemistry Study Guide and Solutions, Chapter 25, Problem 25.1P , additional homework tip  7

Explanation of Solution

The first part of the name suggests that the phenyl ring must be attached directly to the sulfur atom. The second part of the name suggests that the ester is formed from the carboxylic acid which contains a cyclohexyl ring. In IUPAC nomenclature, “thio-“is inserted before the “ate” suffix in the name of the corresponding oxygen ester.

The structure for S-phenyl cyclohexanecarbothioate is shown as below:

Organic Chemistry Study Guide and Solutions, Chapter 25, Problem 25.1P , additional homework tip  8

Conclusion

The structure for S-phenyl cyclohexanecarbothioate is:

Organic Chemistry Study Guide and Solutions, Chapter 25, Problem 25.1P , additional homework tip  9

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Draw the anti-Markovnikov product of the hydration of this alkene. this problem. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for esc esc ☐ Explanation Check F1 1 2 F2 # 3 F3 + $ 14 × 1. BH THE BH3 2. H O NaOH '2 2' Click and drag to start drawing a structure. F4 Q W E R A S D % 905 LL F5 F6 F7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility < & 6 7 27 8 T Y U G H I F8 F9 F10 F11 F12 9 0 J K L P + // command option Z X C V B N M H H rol option command
AG/F-2° V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: -0.93 +0.38 -0.50 -0.51 -0.06 H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3 Acidic solution Basic solution -0.28 -0.50 3--1.12 -1.57 -2.05 -0.89 PO HPO H₂PO₂ →P → PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH P 0.0 -0.5 -1.0- -1.5- -2.0 H.PO, -2.3+ -3 -2 -1 1 2 3 2 H,PO, b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) H,PO 4 S Oxidation stale, N
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