CHEMISTRY 1111 LAB MANUAL >C<
1st Edition
ISBN: 9781307092097
Author: Chang
Publisher: MCG/CREATE
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Question
Chapter 25, Problem 25.19QP
Interpretation Introduction
Interpretation:
Structure of dipeptides should be drawn from the reaction of glycine and alanine.
Concept introduction:
Amino acid monomers linked by amide bonds is called peptides.
A dipeptide molecule contains either one amino acid with two peptide bonds or two amino acids joined by a single peptide bond.
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redraw the flowchart with boxes and molecules written in them
Part I.
a) Elucidate
the structure of compound A using the following information.
• mass spectrum: m+ = 102, m/2=57
312=29
• IR spectrum:
1002.5
% TRANSMITTANCE
Ngg
50
40
30
20
90
80
70
60
MICRONS
5
8
9 10
12
13
14 15 16
19
1740 cm
M
10
0
4000
3600
3200
2800
2400
2000
1800
1600
13
• CNMR
'H
-NMR
Peak
8
ppm (H)
Integration
multiplicity
a
1.5 (3H)
triplet
b
1.3
1.5 (3H)
triplet
C
2.3
1 (2H)
quartet
d
4.1
1 (2H)
quartet
& ppm (c)
10
15
28
60
177 (C=0)
b) Elucidate the structure of compound B using the following information
13C/DEPT NMR 150.9 MHz
IIL
1400
WAVENUMBERS (CM-1)
DEPT-90
DEPT-135
85 80 75
70
65
60
55
50
45 40
35
30 25 20
ppm
1200
1000
800
600
400
•
Part II.
a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below:
• IR spectra
% TRANSMITTANCE
1002.5
90
80
70
60
50
40
30
20
10
0
4000
3600
3200
2800
2400
2000
1800
1600
• Information from 'HAMR
MICRONS
8 9 10
11
14 15 16
19
25
1400
WAVENUMBERS (CM-1)
1200
1000
800
600
400
peak
8 ppm
Integration
multiplicity
a
2.1
1.5 (3H)
Singlet
b
3.6
1 (2H)
singlet
с
3.8
1.5 (3H)
Singlet
d
6.8
1(2H)
doublet
7.1
1(2H)
doublet
Information from 13C-nmR
Normal carbon
29ppm
Dept 135
Dept -90
+
NO peak
NO peak
50 ppm
55 ppm
+
NO peak
114 ppm
t
126 ppm
No peak
NO peak
130 ppm
t
+
159 ppm
No peak
NO peak
207 ppm
по реак
NO peak
Chapter 25 Solutions
CHEMISTRY 1111 LAB MANUAL >C<
Ch. 25 - Prob. 25.1QPCh. 25 - Prob. 25.2QPCh. 25 - Prob. 25.3QPCh. 25 - Prob. 25.4QPCh. 25 - Prob. 25.5QPCh. 25 - Prob. 25.6QPCh. 25 - Prob. 25.7QPCh. 25 - Prob. 25.8QPCh. 25 - Prob. 25.9QPCh. 25 - Prob. 25.10QP
Ch. 25 - Prob. 25.11QPCh. 25 - Prob. 25.12QPCh. 25 - Prob. 25.13QPCh. 25 - Prob. 25.14QPCh. 25 - Prob. 25.15QPCh. 25 - Prob. 25.16QPCh. 25 - Prob. 25.17QPCh. 25 - Prob. 25.18QPCh. 25 - Prob. 25.19QPCh. 25 - Prob. 25.20QPCh. 25 - Prob. 25.21QPCh. 25 - Prob. 25.22QPCh. 25 - Prob. 25.23QPCh. 25 - Prob. 25.24QPCh. 25 - Prob. 25.25QPCh. 25 - Prob. 25.26QPCh. 25 - Discuss the importance of hydrogen bonding in...Ch. 25 - Proteins vary widely in structure, whereas nucleic...Ch. 25 - Prob. 25.29QPCh. 25 - Prob. 25.30QPCh. 25 - Prob. 25.31QPCh. 25 - Prob. 25.32QPCh. 25 - Prob. 25.33QPCh. 25 - Prob. 25.34QPCh. 25 - Prob. 25.35QPCh. 25 - Chemical analysis shows that hemoglobin contains...Ch. 25 - Prob. 25.37QPCh. 25 - What kind of intermolecular forces are responsible...Ch. 25 - Draw structures of the nucleotides containing the...Ch. 25 - Prob. 25.40QPCh. 25 - Prob. 25.41QPCh. 25 - Prob. 25.42QPCh. 25 - Prob. 25.43QPCh. 25 - Prob. 25.44QPCh. 25 - When deoxyhemoglobin crystals are exposed to...Ch. 25 - Prob. 25.46QPCh. 25 - Prob. 25.47QPCh. 25 - Prob. 25.48QPCh. 25 - Prob. 25.49QPCh. 25 - Prob. 25.50QPCh. 25 - Prob. 25.51QPCh. 25 - Assume the energy of hydrogen bonds per base pair...Ch. 25 - Prob. 25.53IME
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- What is/are the product(s) of the following reaction? Select all that apply. * HI A B C OD OH A B OH D Carrow_forwardIn the image, the light blue sphere represents a mole of hydrogen atoms, the purple or teal spheres represent a mole of a conjugate base. A light blue sphere by itself is H+. Assuming there is 2.00 L of solution, answer the following: The Ka of the left & right solution is? The pH of the left & right solution is? The acid on the left & right is what kind of acid?arrow_forwardNonearrow_forward
- Nonearrow_forwardNonearrow_forwardWhat spectral features allow you to differentiate the product from the starting material? Use four separate paragraphs for each set of comparisons. You should have one paragraph each devoted to MS, HNMR, CNMR and IR. 2) For MS, the differing masses of molecular ions are a popular starting point. Including a unique fragmentation is important, too. 3) For HNMR, CNMR and IR state the peaks that are different and what makes them different (usually the presence or absence of certain groups). See if you can find two differences (in each set of IR, HNMR and CNMR spectra) due to the presence or absence of a functional group. Include peak locations. Alternatively, you can state a shift of a peak due to a change near a given functional group. Including peak locations for shifted peaks, as well as what these peaks are due to. Ideally, your focus should be on not just identifying the differences but explaining them in terms of functional group changes.arrow_forward
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