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DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Question
Chapter 25, Problem 22RQ
To determine
The difference in purpose of counterboring and spot facing.
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3. Through hole of 12 mm diameter is to be drilled in a steel plate of 20 mm thickness, drilled spindle
speed is 20 m/min, feed 0.25 mm/rev and drill point angle is 120°, the amount of material removed
at the first 10 sec after full engagement of drill will be ..
(a) 2300, (b) 2400, (c) 2500, (d) 2600, (e) 2700
mm /sec.
A long workpiece, with the length-to-dimeter ratio that exceeds factor 10, is to be
machined. Which workholding should provide the lowest deflection?
Collet in the spindle and a live center in the tailstock
Chuck on the spindle, a live center in the tailstock, and a follower rest
Mandrel
Solid center with a dog and a dog plate on the spindle, a live center in the
tailstock
Faceplate
Chapter 25 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 25 - What functions are performed by the flutes on a...Ch. 25 - What determines the rake angle of a drill? See...Ch. 25 - Basically, what determines what helix angle a...Ch. 25 - When a large-diameter hole is to be drilled, why...Ch. 25 - Equation 25.4 for the MRR for drilling can be...Ch. 25 - Are the recommended surface speeds for spade...Ch. 25 - What can happen when an improperly ground drill is...Ch. 25 - Why are many drilled holes oversize with respect...Ch. 25 - What are the two primary functions of a...Ch. 25 - What is the function of the margins on a twist...
Ch. 25 - What factors tend to cause a drill to drift off...Ch. 25 - The drill shown in Figure 25.13 has coolant...Ch. 25 - Prob. 13RQCh. 25 - Why do cutting fluids for drilling usually have...Ch. 25 - How does a gang-drilling machine differ from a...Ch. 25 - Prob. 16RQCh. 25 - How does the thrust force vary with feed? Why?Ch. 25 - Holding the workpiece by hand when drilling is not...Ch. 25 - Prob. 19RQCh. 25 - In terms of thrust, what is unusual about the...Ch. 25 - Prob. 21RQCh. 25 - Prob. 22RQCh. 25 - What are the primary purposes of reaming?Ch. 25 - What are the advantages of shell reamers?Ch. 25 - A drill that operated satisfactorily for drilling...Ch. 25 - What precautionary procedures should be used when...Ch. 25 - What is the advantage of a spade drill? Is it...Ch. 25 - Prob. 28RQCh. 25 - Why does drill feed increase with drill size?Ch. 25 - Suppose you specified a drilling feed rate that...Ch. 25 - Suppose you wanted to drill a 1.5-in.-diameter...Ch. 25 - How much time will be required to drill the hole...Ch. 25 - What is the metal removal rate when a...Ch. 25 - If the specific horsepower for the steel in...Ch. 25 - If the specific power of an AISI 1020 steel of...Ch. 25 - Prob. 6PCh. 25 - Assume that you are drilling eight holes, equally...Ch. 25 - What machining difficulties should this process...Ch. 25 - Why were the distances between the holes too...
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- What is the major difference between counterboring and spotfacing?arrow_forwardWhat is the name of the circle from which the involute curve is generated? Select one: O a. Base Circle O b. Dedendum Circle O c. None of these options O d. Involute Circle Oe. Fundamental Circle pagearrow_forwardSample Problem 3 How long will it take to mill a % inch by 2 long keyway in a 3 in diameter shafting with a 24 tooth cutter turning at 100 rpm and 0.005 inch feed per tooth?arrow_forward
- 2. Through hole of 12 mm diameter is to be drilled in a steel plate of 20 mm thickness, drilled spindle speed is 20 m/min, feed 0.25 mm/rev and drill point angle is 120°, the amount of material removed at the first 10 sec after full engagement of drill will be mm/sec. (a) 2300, (b) 2400, (c) 2500, (d) 2600, (e) 2700arrow_forwardQUESTION 5 Determine the spindle speed (rpm), the feed rate (in/min) and the cutting power required for turning a 1º diameter copper rod with a depth of cut of 0.1" using a cemented carbide tool. O N=287 RPM, F-25.8 in/min, P=9.7 hp ON=2866 RPM, F=258 in/min, P=97 hp ON=1146 RPM, F-25.8 in/min, P=97 hp O N= 11460 RPM, F-340 in/min, P=130 hp ON= 1146 RPM, F-34 inimin, P= 13 hp ON= 115 RPM, F-3.4 in/min, P=1.3 hp QUESTION 6 It is required to face mill an aluminum block to size it down from 2" to 1.5" thick using a 3" diameter 2-toothed carbide cutting tool. The block is 6.0" wide and 6" long. The entire tool diameter engages the workpiece during the cut. Calculate the recommended spindle speed in revolutions per minute, feed per tooth, and cutting power required. O N=1529 RPM, f= 0.026 in/rev/tooth, P = 36 hp O N-3820 RPM, f= 26 in/revitooth, P=27 hp O N-3820 RPM, f= 0.052 in/rew/tooth, P=27 hp ON-382 RPM, F= 0.026 in/revitooth, P = 0.027 hp O N-3820 RPM, f= 0.052 in/rev/tooth, P=2.7 hp…arrow_forwardWhat is nutation in gyroscopic motion?arrow_forward
- Multiple grooving is most suited for: 4 1 2 3 O Rough grooving when the depth is bigger than the width O Minimizing vibrations and radial forces Machining steel and stainless steel and when the width of the groove is larger than the deptharrow_forwardQuestion 21 and 22arrow_forwardA high-speed heavy duty plain milling cutter 4 inches in diameter with 12 teeth is to be used. Each tooth s expected to remove 0.006 inch. What is the feed per revolution? 2. The feed per revolution is 0.0072 inch/rev and the machine is set for 120 rev/min. Find the feed in inch per minutearrow_forward
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