Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 25, Problem 22QLP
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Explain the differences in the functions of a turret and of a spindle in turning centers.
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Explain the difference between concentric turning and eccentric turning.
In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)
Explain with neat line diagram the working principle of simple gear train that can be use in lathe machines and also define the train value of the simple gear train.
Chapter 25 Solutions
Manufacturing Engineering & Technology
Ch. 25 - Describe the distinctive features of machining...Ch. 25 - Explain how the tooling system in a machining...Ch. 25 - Explain the trends in materials used for...Ch. 25 - Is there any difference between chatter and...Ch. 25 - What are the differences between forced and...Ch. 25 - Explain the importance of foundations in...Ch. 25 - Explain why automated pallet changers and...Ch. 25 - What types of materials are machine-tool bases...Ch. 25 - What is meant by the modular construction of...Ch. 25 - What is a hexapod? What are its advantages?
Ch. 25 - What factors contribute to costs in machining...Ch. 25 - List the reasons that temperature is important in...Ch. 25 - Explain the technical and economic factors that...Ch. 25 - Spindle speeds in machining centers vary over a...Ch. 25 - Explain the importance of stiffness and damping of...Ch. 25 - Are there machining operations described in...Ch. 25 - How important is the control of cutting-fluid...Ch. 25 - Review Fig. 25.10 on modular machining centers,...Ch. 25 - Prob. 19QLPCh. 25 - Describe the adverse effects of vibration and...Ch. 25 - Describe some specific situations in which thermal...Ch. 25 - Prob. 22QLPCh. 25 - Prob. 23QLPCh. 25 - Prob. 24QLPCh. 25 - List the parameters that influence the temperature...Ch. 25 - List and explain factors that contribute to poor...Ch. 25 - Prob. 27QLPCh. 25 - Prob. 28QLPCh. 25 - Describe types and sizes of workpieces that would...Ch. 25 - Prob. 30QLPCh. 25 - Explain the advantages and disadvantages of...Ch. 25 - What are the advantages and disadvantages of (a)...Ch. 25 - What would be the advantages and limitations of...Ch. 25 - Explain how you would go about reducing each of...Ch. 25 - Describe workpieces that would not be suitable for...Ch. 25 - Give examples of forced vibration or self-excited...Ch. 25 - A machining-center spindle and tool extend 10 in....Ch. 25 - Using the data given in the example, estimate the...Ch. 25 - A machining-center spindle and tool extend 12 in....Ch. 25 - In the production of a machined valve, the labor...Ch. 25 - Estimate the optimum cutting speed in Problem...Ch. 25 - Prob. 42QTPCh. 25 - If you were the chief engineer in charge of the...Ch. 25 - Prob. 45SDPCh. 25 - Make a list of components of machine tools that...Ch. 25 - The cost of machining and turning centers is...Ch. 25 - Prob. 49SDPCh. 25 - Describe your thoughts on whether or not it is...Ch. 25 - Prob. 51SDPCh. 25 - Prob. 53SDP
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- In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)arrow_forwardCalculate the spindle speed (rpm) for turning operation when the cutting speed is 107.00 m/min and external diameter is D44.00 mm? (Two decimal places; Don't input units.) Your Answer: Answerarrow_forwardIn a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed-9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution) L Tm- 1,= Nf N AD, vT" = C %3| AD,L Tm fvarrow_forward
- A cemented carbide tool is used to turn a part with length = 18.0 in and diameter = 3.0 in. The parameters in the Taylor equation are: n = 0.27 and C = 1200. The rate for the operator and machine tool = $33.00/hr, and the tooling cost per cutting edge = $2.00. It takes 3.0 min to load and unload the workpart and 1.50 min to change tools. The feed = 0.013 in/rev. Determine: Cutting speed for maximum production rate, Tool life in min of cutting, and Cycle time and cost per unit of product.arrow_forwardThe end of a large tubular workpart is to be faced on a NC vertical boring mill. The part has an outside diameter of 38.0 in and an inside diameter of 24.0 in. If the facing operation is performed at a rotational speed of 40.0 rev/min, feed of 0.015 in/rev, and depth of cut of 0.180 in, determine (a) the cutting time to complete the facing operation and the cutting speeds and metal removal rates at the beginning and end of the cut.arrow_forwardCalculate the spindle speed for a Lathe Machine, if the cutting speed for a mild steel material workpiece is 34 m/min and the diameter of the cylindrical workpiece is 46 mm.arrow_forward
- Problem #2: Do a comparison between turning Vs. milling operations use some graphs if possible.arrow_forwardConsider a profile milling operation, where the initial (stock) geometry has (X,Y,Z) dimensions of 100 mm x 75 mm x 50 mm. The target part has dimensions of 95 mm x 70 mm x 50 mm. The target part is located in the centre of the stock part, i.e. the stock to be removed from all sides is equal. The operation has a cutting time of 1 minute. The tool axis is along the Z direction and the tool diameter is 12 mm having 6 cutting edges. The takes place at 54m/min feed rate of 0.2 mm/rev/tooth. Calculate the axial depth of cut ? process at aarrow_forwardA turning operation is performed with HSS tooling on mild steel, with Taylor tool life parameters n = 0.12, C = 60 m/min. Work part length = 450 mm and diameter = 80 mm. Feed = 0.20 mm/rev. Handling time per piece = 4.0 min, and tool change time = 1.5 min. Cost of machine and operator = $27/hr, and tooling cost = $2 per cutting edge. Find the a. cutting speed for maximum production rate and b. cutting speed for minimum cost Equations used n *-=c(")* Vmax = C 1-n Tt Vmin = C =c(₁" n 1 n Co n CoTt + Ct narrow_forward
- In the lathe machine, the diameter of workpart 35mm is turned at 100 rpm, depth of cut 0.125 mm, length of continuous chip for one revolution of workpart = 60mm, length undeformed chip= 100.53mm, rake angle = 35°, coefficient of friction= 1.5 and resultant cutting force=215.5 N. Calculate: 1- Horizontal cutting force of the tool on the workpart and vertical cutting force required to hold the tool against the work. 2- The forces components applied against the chip by the tool. 3- Velocity of chip relative to the tool and workpart. 4- The percentage of total energy dissipated due to friction along the shear plane, and the friction at the tool-chip interface.arrow_forwardCalculate the time required to machine a workpiece 170 mm long, 60 mm diameter to 165 mm long 50 mm diameter. The workpiece rotates at 440 rpm, feed is 0.3 mm/rev and maximum depth of cut is 2 mm. Assume total approach and overtravel distance as 5 mm for turning operation.arrow_forwardDifferentiate between (i) Plain Turning and Facing operation (ii)Taper Turning and Knurling operationarrow_forward
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HOME SHOP JIGS & FIXTURES PART 1, TYPES OF JIGS & ACCESSORIES AND THE THEORIE BEHIND THE TOOLS; Author: THATLAZYMACHINIST;https://www.youtube.com/watch?v=EXYqi42JimI;License: Standard Youtube License