EP INTRODUCTION TO PROBABILITY+STAT.
14th Edition
ISBN: 2810019974203
Author: Mendenhall
Publisher: CENGAGE L
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Chapter 2.5, Problem 2.23E
a.
To determine
To find: The approximate value of
b.
To determine
To find:The value of
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How many apps? According to a website, the mean number of apps on a smartphone in the United States is 82. Assume
the number of apps is normally distributed with mean 82 and standard deviation 30.
Part 1 of 2
(a) What proportion of phones have more than 47 apps? Round the answer to four decimal places.
The proportion of phones that have more than 47 apps is 0.8783
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You are provided with data that includes all 50 states of the United States. Your task is to draw a sample of:
20 States using Random Sampling (2 points: 1 for random number generation; 1 for random sample)
10 States using Systematic Sampling (4 points: 1 for random numbers generation; 1 for generating random sample different from the previous answer; 1 for correct K value calculation table; 1 for correct sample drawn by using systematic sampling) (For systematic sampling, do not use the original data directly. Instead, first randomize the data, and then use the randomized dataset to draw your sample. Furthermore, do not use the random list previously generated, instead, generate a new random sample for this part. For more details, please see the snapshot provided at the end.) You are provided with data that includes all 50 states of the United States. Your task is to draw a sample of: o 20 States using Random Sampling (2 points: 1 for random number generation; 1 for random sample) o…
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Listed in the accompanying table are weights (kg) of randomly selected U.S. Army male personnel measured in 1988 (from "ANSUR I 1988") and different weights (kg) of randomly selected U.S.
Army male personnel measured in 2012 (from "ANSUR II 2012"). Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not
assume that the population standard deviations are equal. Complete parts (a) and (b).
Click the icon to view the ANSUR data.
a. Use a 0.05 significance level to test the claim that the mean weight of the 1988…
Chapter 2 Solutions
EP INTRODUCTION TO PROBABILITY+STAT.
Ch. 2.2 - You are given n=5 measurements: 0, 5, 1, 1,3. Draw...Ch. 2.2 - Prob. 2.2ECh. 2.2 - Prob. 2.3ECh. 2.2 - Auto Insurance The cost of automobile insurance...Ch. 2.2 - Prob. 2.5ECh. 2.2 - Prob. 2.6ECh. 2.2 - Prob. 2.7ECh. 2.2 - Prob. 2.8ECh. 2.2 - Prob. 2.9ECh. 2.2 - Prob. 2.10E
Ch. 2.2 - Prob. 2.11ECh. 2.2 - Prob. 2.12ECh. 2.3 - You are given n=5 measurements: 2, 1, 1,3,5. a....Ch. 2.3 - Prob. 2.14ECh. 2.3 - Prob. 2.15ECh. 2.3 - Prob. 2.16ECh. 2.3 - Prob. 2.17ECh. 2.3 - Utility Bills in Southern CaliforniaThe monthly...Ch. 2.5 - Prob. 2.19ECh. 2.5 - Prob. 2.20ECh. 2.5 - A distribution of measurements is relatively...Ch. 2.5 - Prob. 2.22ECh. 2.5 - Prob. 2.23ECh. 2.5 - Packaging Hamburger Meat The data listed here are...Ch. 2.5 - Breathing Rates Is your breathing rate normal?...Ch. 2.5 - Prob. 2.26ECh. 2.5 - Social Security Numbers A group of70 students were...Ch. 2.5 - Prob. 2.28ECh. 2.5 - Prob. 2.29ECh. 2.5 - Prob. 2.30ECh. 2.5 - Timber Tracts To estimate the amount of lumber in...Ch. 2.5 - Prob. 2.32ECh. 2.5 - Prob. 2.33ECh. 2.5 - Prob. 2.34ECh. 2.5 - Prob. 2.35ECh. 2.5 - Prob. 2.36ECh. 2.5 - Prob. 2.37ECh. 2.5 - Prob. 2.38ECh. 2.5 - Prob. 2.39ECh. 2.7 - Prob. 2.40ECh. 2.7 - Find the five-number summary and the IQR forthese...Ch. 2.7 - Given the following data set: 2.3, 1.0, 2.1, 6.5,...Ch. 2.7 - Given the following data set: .23, .30, .35, .41,...Ch. 2.7 - Construct a box plot for these data and...Ch. 2.7 - Construct a box plot for these data and...Ch. 2.7 - If you scored at the 69th percentile on a...Ch. 2.7 - Mercury Concentration in DolphinsEnvironmental...Ch. 2.7 - Hamburger Meat The weights (in pounds) of the 27...Ch. 2.7 - Comparing NFL Quarterbacks How does Aaron Rodgers,...Ch. 2.7 - Presidential Vetoes The set of presidential vetoes...Ch. 2.7 - Survival Times Altman and Bland report the...Ch. 2.7 - Utility Bills in Southern California, again The...Ch. 2.7 - What’s Normal? again Refer to Exercise1.67 and...Ch. 2 - Raisins The number of raisins in each of...Ch. 2 - Prob. 2.55SECh. 2 - Prob. 2.56SECh. 2 - A Recurring IIIness Refer to Exercise 1.26 and...Ch. 2 - Prob. 2.58SECh. 2 - Prob. 2.59SECh. 2 - Tuna Fish, again Refer to Exercise 2.8. Theprices...Ch. 2 - Prob. 2.61SECh. 2 - Chloroform According to the EPA, Chloroform, which...Ch. 2 - Prob. 2.63SECh. 2 - Sleep and the College Student How muchsleep do you...Ch. 2 - Prob. 2.65SECh. 2 - Prob. 2.66SECh. 2 - Polluted Seawater Petroleum pollution in seasand...Ch. 2 - Prob. 2.68SECh. 2 - Prob. 2.69SECh. 2 - Prob. 2.70SECh. 2 - Prob. 2.71SECh. 2 - Prob. 2.72SECh. 2 - Prob. 2.73SECh. 2 - Prob. 2.74SECh. 2 - TV Commercials The mean duration oftelevision...Ch. 2 - Prob. 2.76SECh. 2 - Prob. 2.77SECh. 2 - Prob. 2.78SECh. 2 - Prob. 2.79SECh. 2 - Prob. 2.80SECh. 2 - Prob. 2.81SECh. 2 - Prob. 2.82SECh. 2 - Prob. 2.83SECh. 2 - Prob. 2.84SECh. 2 - Prob. 2.85SE
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- solving problem 1arrow_forwardselect bmw stock. you can assume the price of the stockarrow_forwardThis problem is based on the fundamental option pricing formula for the continuous-time model developed in class, namely the value at time 0 of an option with maturity T and payoff F is given by: We consider the two options below: Fo= -rT = e Eq[F]. 1 A. An option with which you must buy a share of stock at expiration T = 1 for strike price K = So. B. An option with which you must buy a share of stock at expiration T = 1 for strike price K given by T K = T St dt. (Note that both options can have negative payoffs.) We use the continuous-time Black- Scholes model to price these options. Assume that the interest rate on the money market is r. (a) Using the fundamental option pricing formula, find the price of option A. (Hint: use the martingale properties developed in the lectures for the stock price process in order to calculate the expectations.) (b) Using the fundamental option pricing formula, find the price of option B. (c) Assuming the interest rate is very small (r ~0), use Taylor…arrow_forward
- Discuss and explain in the picturearrow_forwardBob and Teresa each collect their own samples to test the same hypothesis. Bob’s p-value turns out to be 0.05, and Teresa’s turns out to be 0.01. Why don’t Bob and Teresa get the same p-values? Who has stronger evidence against the null hypothesis: Bob or Teresa?arrow_forwardReview a classmate's Main Post. 1. State if you agree or disagree with the choices made for additional analysis that can be done beyond the frequency table. 2. Choose a measure of central tendency (mean, median, mode) that you would like to compute with the data beyond the frequency table. Complete either a or b below. a. Explain how that analysis can help you understand the data better. b. If you are currently unable to do that analysis, what do you think you could do to make it possible? If you do not think you can do anything, explain why it is not possible.arrow_forward
- 0|0|0|0 - Consider the time series X₁ and Y₁ = (I – B)² (I – B³)Xt. What transformations were performed on Xt to obtain Yt? seasonal difference of order 2 simple difference of order 5 seasonal difference of order 1 seasonal difference of order 5 simple difference of order 2arrow_forwardCalculate the 90% confidence interval for the population mean difference using the data in the attached image. I need to see where I went wrong.arrow_forwardMicrosoft Excel snapshot for random sampling: Also note the formula used for the last column 02 x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51)) A B 1 No. States 2 1 ALABAMA Rand No. 0.925957526 3 2 ALASKA 0.372999976 4 3 ARIZONA 0.941323044 5 4 ARKANSAS 0.071266381 Random Sample CALIFORNIA NORTH CAROLINA ARKANSAS WASHINGTON G7 Microsoft Excel snapshot for systematic sampling: xfx INDEX(SD52:50551, F7) A B E F G 1 No. States Rand No. Random Sample population 50 2 1 ALABAMA 0.5296685 NEW HAMPSHIRE sample 10 3 2 ALASKA 0.4493186 OKLAHOMA k 5 4 3 ARIZONA 0.707914 KANSAS 5 4 ARKANSAS 0.4831379 NORTH DAKOTA 6 5 CALIFORNIA 0.7277162 INDIANA Random Sample Sample Name 7 6 COLORADO 0.5865002 MISSISSIPPI 8 7:ONNECTICU 0.7640596 ILLINOIS 9 8 DELAWARE 0.5783029 MISSOURI 525 10 15 INDIANA MARYLAND COLORADOarrow_forward
- Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined. 1.What percent of the refunds are more than $3,500? 2. What percent of the refunds are more than $3500 but less than $3579? 3. What percent of the refunds are more than $3325 but less than $3579?arrow_forwardA normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts? 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the answer of the second part.) 2. Compute the probability of a value greater than 55.0. Use the same formula, x=55 and subtract the answer from 1. 3. Compute the probability of a value between 52.0 and 55.0. (The question requires finding probability value between 52 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 52, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forwardIf a uniform distribution is defined over the interval from 6 to 10, then answer the followings: What is the mean of this uniform distribution? Show that the probability of any value between 6 and 10 is equal to 1.0 Find the probability of a value more than 7. Find the probability of a value between 7 and 9. The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be: More than $27? Less than or equal to $24? The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. What is the mean amount of rainfall for the month? What is the probability of less than an inch of rain for the month? What is the probability of exactly 1.00 inch of rain? What is the probability of more than 1.50 inches of rain for the month? The best way to solve this problem is begin by a step by step creating a chart. Clearly mark the range, identifying the…arrow_forward
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