Laboratory Experiments For Chemistry: The Central Science, Si Edition
14th Edition
ISBN: 9781292221335
Author: Theodore E. Brown
Publisher: PEARSON
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Textbook Question
Chapter 24.7, Problem 24.8.1PE
How many chiral carbon atoms are there in the open-chain form of fructose (Figure 24.19)?
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Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal energy
Divide the…
Please correct answer and don't used hand raiting
Please correct answer and don't used hand raiting
Chapter 24 Solutions
Laboratory Experiments For Chemistry: The Central Science, Si Edition
Ch. 24.2 - Prob. 24.1.1PECh. 24.2 - Prob. 24.1.2PECh. 24.2 - How many hydrogen atoms are in 2, 2-...Ch. 24.2 - Prob. 24.2.2PECh. 24.3 - Prob. 24.3.1PECh. 24.3 - Prob. 24.3.2PECh. 24.3 - Prob. 24.4.1PECh. 24.3 - Prob. 24.4.2PECh. 24.3 - Prob. 24.5.1PECh. 24.3 - Prob. 24.5.2PE
Ch. 24.4 - Prob. 24.6.1PECh. 24.4 - Prob. 24.6.2PECh. 24.7 - Prob. 24.7.1PECh. 24.7 - Practice Exercise 2 Name the dipeptide and give...Ch. 24.7 - How many chiral carbon atoms are there in the...Ch. 24.7 - Prob. 24.8.2PECh. 24 - Prob. 1DECh. 24 - Prob. 1ECh. 24 - Prob. 2ECh. 24 - Prob. 3ECh. 24 - Prob. 4ECh. 24 - Prob. 5ECh. 24 - Prob. 6ECh. 24 - Prob. 7ECh. 24 - Prob. 8ECh. 24 - Prob. 9ECh. 24 - Prob. 10ECh. 24 - Prob. 11ECh. 24 - Prob. 12ECh. 24 - Prob. 13ECh. 24 - Prob. 14ECh. 24 - Prob. 15ECh. 24 - Prob. 16ECh. 24 - Prob. 17ECh. 24 - Prob. 18ECh. 24 - Prob. 19ECh. 24 - Prob. 20ECh. 24 - Prob. 21ECh. 24 - Prob. 22ECh. 24 - Prob. 23ECh. 24 - Prob. 24ECh. 24 - Prob. 25ECh. 24 - Prob. 26ECh. 24 - Prob. 27ECh. 24 - Prob. 28ECh. 24 - Prob. 29ECh. 24 - Prob. 30ECh. 24 - Prob. 31ECh. 24 - Prob. 32ECh. 24 - Prob. 33ECh. 24 - Prob. 34ECh. 24 - Prob. 35ECh. 24 - Prob. 36ECh. 24 - Prob. 37ECh. 24 - Prob. 38ECh. 24 - Prob. 39ECh. 24 - Describe the intermediate that is thought to form...Ch. 24 - Prob. 41ECh. 24 - Prob. 42ECh. 24 - Prob. 43ECh. 24 - Prob. 44ECh. 24 - Prob. 45ECh. 24 - Prob. 46ECh. 24 - Prob. 47ECh. 24 - Prob. 48ECh. 24 - Prob. 49ECh. 24 - Prob. 50ECh. 24 - Prob. 51ECh. 24 - Prob. 52ECh. 24 - Prob. 53ECh. 24 - Prob. 54ECh. 24 - Prob. 55ECh. 24 - Prob. 56ECh. 24 - Prob. 57ECh. 24 - Prob. 58ECh. 24 - Prob. 59ECh. 24 - Prob. 60ECh. 24 - Prob. 61ECh. 24 - Prob. 62ECh. 24 - Prob. 63ECh. 24 - Prob. 64ECh. 24 - Prob. 65ECh. 24 - Prob. 66ECh. 24 - Prob. 67ECh. 24 - Prob. 68ECh. 24 - Prob. 69ECh. 24 - Prob. 70ECh. 24 - Prob. 71ECh. 24 - Prob. 72ECh. 24 - Prob. 73ECh. 24 - Prob. 74ECh. 24 - Prob. 75ECh. 24 - Prob. 76ECh. 24 - Prob. 77ECh. 24 - Prob. 78ECh. 24 - Prob. 79ECh. 24 - Prob. 80ECh. 24 - Prob. 81AECh. 24 - Prob. 82AECh. 24 - Prob. 83AECh. 24 - Prob. 84AECh. 24 - Prob. 85AECh. 24 - Prob. 86AECh. 24 - Prob. 87AECh. 24 - Prob. 88AECh. 24 - Prob. 89AECh. 24 - Prob. 90AECh. 24 - Prob. 91AECh. 24 - Prob. 92AECh. 24 - Prob. 93AECh. 24 - Prob. 94AECh. 24 - Prob. 95IECh. 24 - Prob. 96IECh. 24 - Prob. 97IECh. 24 - Prob. 98IECh. 24 - Prob. 99IECh. 24 - A typical amino acid with one amino group and one...Ch. 24 - Prob. 101IECh. 24 - Prob. 102IE
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