21ST CENT.ASTRONOMY(LL)W/CODE WKBK PKG.
6th Edition
ISBN: 9780393874921
Author: PALEN
Publisher: Norton, W. W. & Company, Inc.
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Chapter 24.1, Problem 24.1CYU
To determine
Meaning of organism Extremophiles
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It is estimated that the total amount of oxygen (O2) contained in BIFs is equivalent to 6.6% of the oxygen present in the modern atmosphere. This is quite impressive given that the atmosphere during Archaean and early Proterozoic times was largely devoid of oxygen! Therefore, this reflects the photosynthetic efficiency of the early biosphere, coupled with its operation over long periods of time. Knowing that the mass of the modern atmosphere is 5.01×1018 kg, of which 21% is oxygen, what is the mass (in kilograms) of oxygen contained within BIFs?
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Chapter 24 Solutions
21ST CENT.ASTRONOMY(LL)W/CODE WKBK PKG.
Ch. 24.1 - Prob. 24.1CYUCh. 24.2 - Prob. 24.2CYUCh. 24.3 - Prob. 24.3ACYUCh. 24.3 - Prob. 24.3BCYUCh. 24.4 - Prob. 24.4CYUCh. 24 - Prob. 1QPCh. 24 - Prob. 2QPCh. 24 - Prob. 3QPCh. 24 - Prob. 4QPCh. 24 - Prob. 5QP
Ch. 24 - Prob. 6QPCh. 24 - Prob. 7QPCh. 24 - Prob. 8QPCh. 24 - Prob. 9QPCh. 24 - Prob. 10QPCh. 24 - Prob. 11QPCh. 24 - Prob. 12QPCh. 24 - Prob. 13QPCh. 24 - Prob. 14QPCh. 24 - Prob. 15QPCh. 24 - Prob. 16QPCh. 24 - Prob. 17QPCh. 24 - Prob. 18QPCh. 24 - Prob. 20QPCh. 24 - Prob. 21QPCh. 24 - Prob. 22QPCh. 24 - Prob. 23QPCh. 24 - Prob. 24QPCh. 24 - Prob. 25QPCh. 24 - Prob. 26QPCh. 24 - Prob. 27QPCh. 24 - Prob. 29QPCh. 24 - Prob. 30QP
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- Which of the following statements about the "tree of life" is correct? Before Carl Woese, all cellular life forms were classified into five kingdoms: Monera, Fungi, Plants, Animals, and Protists. Using rRNA genes for phylogenetic reconstruction, Carl Woese uncovered a previously unrecognized group that was thought to be bacteria. Afterward, all cellular life forms were classified into three domains: Archaea, Bacteria, and Eucarya. It is found that the relationship among Archaea, Bacteria, and Eucarya changes, depending on which gene was used for phylogenetic reconstruction. All of the abovearrow_forwardThe Endangered Species Act defines species in Section 3(15) to include ''any subspecies of fish or wildlife or plants, and any distinct population segment of any species of vertebrate fish or wildlife which interbreeds when mature." This is basically applying the Biological species concept Morphological species concept Phylogenetic species concept None of the abovearrow_forwardIn general will procyon have a long or short lifespan?arrow_forward
- If life is based on information, what is that information?arrow_forwardA certain strain of bacteria will divide itself from 1 to 2 every to [minute]. As a result, its population can be modeled as N (t) = No2. ---(eq 1) N(t) is the population at time t, NO is the population at the beginning = 100, t = time you wait [minute]. You prepare 6 dishes. Each dish contains 100 living bacteria at the beginning. Then you wait for 20 mins, freeze the first dish to stop the bacteria in the dish from growing. Then wait for another 20 mins, freeze the second dish (i.e. the total growth time for the second dish is 40 min). Proceed to the next dish in the similar process until all 6 dishes are done. After counting all the dish, you collect the data between time and population as follow: t(min) N(t) 20 132 220 40 60 311 80 369 100 622 120 836 Find to (the time for bacteria to divide itself). Answer in [min] Note: if you apply log function on both sides of eq 1 you get In (N (t)) =t. n2 + In(No). ---(eq 2)arrow_forwardSuppose a species of bacteria divides once every 20 minutes. You start with a single bacterium on your unrefrigerated ham and cheese sandwich at 8:00 am. Show that when you sit down to lunch at noon, there will be 4096 bacteria on your sandwich.arrow_forward
- Small birds like that in (Figure 1) can migrate over long distances without feeding, storing energy mostly as fat rather than carbohydrate. Fat is a good form of energy storage because it provides the most energy per unit mass: 1.00 grams of fat provides about 9.40 (food) Calories, compared to 4.20 (food) Calories per 1.00 grams of carbohydrate. Remember that Calories associated with food, which are always capitalized, are not exactly the same as calories used in physics or chemistry, even though they have the same name. More specifically, one food Calorie is equal to 1000 calories of mechanical work or 4184 joules. Therefore, in this problem use the conversion factor 1 Cal = 4184 J. Figure 1 of 1 > Review | Constants Consider a bird that flies at an average speed of 10.7 m/s and releases energy from its body fat reserves at an average rate of 3.70 W (this rate represents the power consumption of the bird). Assume that the bird consumes 4.00 g of fat to fly over a distance do without…arrow_forwardSmall birds like that in (Figure 1) can migrate over long distances without feeding, storing energy mostly as fat rather than carbohydrate. Fat is a good form of energy storage because it provides the most energy per unit mass: 1.00 grams of fat provides about 9.40 (food) Calories, compared to 4.20 (food) Calories per 1.00 grams of carbohydrate. Remember that Calories associated with food, which are always capitalized, are not exactly the same as calories used in physics or chemistry, even though they have the same name. More specifically, one food Calorie is equal to 1000 calories of mechanical work or 4184 joules. Therefore, in this problem use the conversion factor 1Cal=4184J. Consider a bird that flies at an average speed of 10.7 m/s and releases energy from its body fat reserves at an average rate of 3.70 W (this rate represents the power consumption of the bird). Assume that the bird consumes 4.00g of fat to fly over a distance db without stopping for feeding. How far will the…arrow_forwardSmall birds like that in (Figure 1) can migrate over long distances without feeding, storing energy mostly as fat rather than carbohydrate. Fat is a good form of energy storage because it provides the most energy per unit mass: 1.00 grams of fat provides about 9.40 (food) Calories, compared to 4.20 (food) Calories per 1.00 grams of carbohydrate. Remember that Calories associated with food, which are always capitalized, are not exactly the same as calories used in physics or chemistry, even though they have the same name. More specifically, one food Calorie is equal to 1000 calories of mechanical work or 4184 joules. Therefore, in this problem use the conversion factor 1 Cal 4184 J. Figure 1 of 1 ▸ View Available Hint(s) db = 455 km Submit Previous Answers ▾ Part B ▶ How many grams of carbohydrate mcarbwould the bird have to consume to travel the same distance db? Express your answer in grams View Available Hint(s) Correct mcarb 8.95 g Submit Part C Previous Answers Correct This is more…arrow_forward
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