Chapter 24, Problem 80QP

Interpretation Introduction

Interpretation:

The volume of bromine is to be calculated with given volume, pressure, and temperature.

Concept introduction:

The ideal gas equation is as:

$PV=n\text{R}T$

Here, $P$ is pressure and its unit is $\text{atm}$, $V$ represent volume and its unit is $\text{L}$, $n$ represents number of moles, $\text{R}$ is the gas constant and its value is $\text{0}{\text{.0821 L atm mol}}^{-\text{1}}{\text{K}}^{-\text{1}}$, and $T$ represents temperature and its unit is $\text{K (Kelvin)}$.

If number of moles of two compound are same, the relationship can be expressed as: $\frac{{\text{P}}_{\text{1}}{\text{V}}_{\text{1}}}{{\text{T}}_{\text{1}}}\text{=}\frac{{\text{P}}_{\text{2}}{\text{V}}_{\text{2}}}{{\text{T}}_{\text{2}}}$

The volume of compound can be calculated as: ${\text{V}}_{\text{2}}\text{=}\left(\frac{{\text{P}}_{\text{1}}{\text{V}}_{\text{1}}}{{\text{T}}_{\text{1}}}\right)\left(\frac{{\text{T}}_{\text{2}}}{{\text{P}}_{\text{2}}}\right)$