(a)
Interpretation:
Haworth projection for given compounds should be drawn.
Concept introduction:
The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.
In Haworth projection, oxygen atom is placed in back right corner,
Furanose: A five-member closed chain form of a monosaccharide.
Pyranose: A six-member cyclic form of a monosaccharide.
To find: Haworth projection for given molecule
(b)
Interpretation:
Haworth projection for given compounds should be drawn.
Concept introduction:
The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.
In Haworth projection, oxygen atom is placed in back right corner,
Furanose: A five-member closed chain form of a monosaccharide.
Pyranose: A six-member cyclic form of a monosaccharide.
To find: Haworth projection for given molecule
(c)
Interpretation:
Haworth projection for given compounds should be drawn.
Concept introduction:
The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.
In Haworth projection, oxygen atom is placed in back right corner,
Furanose: A five-member closed chain form of a monosaccharide.
Pyranose: A six-member cyclic form of a monosaccharide.
To find: Haworth projection for given molecule
(d)
Interpretation:
Haworth projection for given compounds should be drawn.
Concept introduction:
The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.
In Haworth projection, oxygen atom is placed in back right corner,
Furanose: A five-member closed chain form of a monosaccharide.
Pyranose: A six-member cyclic form of a monosaccharide.
To find: Haworth projection for given molecule
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Chapter 24 Solutions
ORGANIC CHEMISTRY-PRINT MULTI TERM
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- 3. Use Kapustinskii's equation and data from Table 4.10 in your textbook to calculate lattice energies of Cu(OH)2 and CuCO3 (4 points)arrow_forward2. Copper (II) oxide crystalizes in monoclinic unit cell (included below; blue spheres 2+ represent Cu²+, red - O²-). Use Kapustinski's equation (4.5) to calculate lattice energy for CuO. You will need some data from Resource section of your textbook (p.901). (4 points) CuOarrow_forwardWhat is the IUPAC name of the following compound? OH (2S, 4R)-4-chloropentan-2-ol O (2R, 4R)-4-chloropentan-2-ol O (2R, 4S)-4-chloropentan-2-ol O(2S, 4S)-4-chloropentan-2-olarrow_forward
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