Consider an invertible linear transformation T ( x → ) = A x → from ℝ m to ℝ n , with inverse L = T − 1 from ℝ n to ℝ m . In Exercise 2.2.29 we show that L is a linear transformation, so that L ( y → ) = B y → for some m × n matrixB. Use the equations B A = I n , and A B = I m , to showthat n = m . hint: Think about the number of solutionsof the linear systems A x → = 0 → and B y → = 0 → .
Consider an invertible linear transformation T ( x → ) = A x → from ℝ m to ℝ n , with inverse L = T − 1 from ℝ n to ℝ m . In Exercise 2.2.29 we show that L is a linear transformation, so that L ( y → ) = B y → for some m × n matrixB. Use the equations B A = I n , and A B = I m , to showthat n = m . hint: Think about the number of solutionsof the linear systems A x → = 0 → and B y → = 0 → .
Solution Summary: The author explains the value of n, and the inverse of the transformation, which is L=T-1.
Consider an invertible linear transformation
T
(
x
→
)
=
A
x
→
from
ℝ
m
to
ℝ
n
, with inverse
L
=
T
−
1
from
ℝ
n
to
ℝ
m
. In Exercise 2.2.29 we show that L is a linear transformation, so that
L
(
y
→
)
=
B
y
→
for some
m
×
n
matrixB. Use the equations
B
A
=
I
n
, and
A
B
=
I
m
, to showthat
n
=
m
. hint: Think about the number of solutionsof the linear systems
A
x
→
=
0
→
and
B
y
→
=
0
→
.
Solve the system of equation for y using Cramer's rule. Hint: The
determinant of the coefficient matrix is -23.
-
5x + y − z = −7
2x-y-2z = 6
3x+2z-7
eric
pez
Xte
in
z=
Therefore, we have
(x, y, z)=(3.0000,
83.6.1 Exercise
Gauss-Seidel iteration with
Start with (x, y, z) = (0, 0, 0). Use the convergent Jacobi i
Tol=10 to solve the following systems:
1.
5x-y+z = 10
2x-8y-z=11
-x+y+4z=3
iteration (x
Assi 2
Assi 3.
4.
x-5y-z=-8
4x-y- z=13
2x - y-6z=-2
4x y + z = 7
4x-8y + z = -21
-2x+ y +5z = 15
4x + y - z=13
2x - y-6z=-2
x-5y- z=-8
realme Shot on realme C30
2025.01.31 22:35
f
Use Pascal's triangle to expand the binomial
(6m+2)^2
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