EBK MATHEMATICS FOR MACHINE TECHNOLOGY
EBK MATHEMATICS FOR MACHINE TECHNOLOGY
8th Edition
ISBN: 9781337798396
Author: SMITH
Publisher: CENGAGE LEARNING - CONSIGNMENT
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 24, Problem 26A
To determine

The amount of carbon needed to produce 2.60 tons of carbon steel required in the production of each type of tool.

Expert Solution & Answer
Check Mark

Answer to Problem 26A

  59.8 pounds of carbon is required to make twist drill.

  39 pounds of carbon is required to make wrench.

  54.6 pounds of carbon is required to make threading die.

  65 pounds of carbon is required to make ordinary file.

  49.4 pounds of carbon is required to make Machinist's hammer.

  44.2 pounds of carbon is required to make Chuck jaw.

Explanation of Solution

Given information:

Below table is given for amount of carbon needed for different tool. Amount of carbon steel is 2.60 tons.

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 24, Problem 26A

Calculation:

As per the given information amount of carbon steel is 2.60 tons.

Need to find the required percentage of carbon for different tool.

  1.Twist drill :

As we know the proportion to find percentage is given as

  PB=R100   where, P=percentage, B= base and R=rate

Here, amount of carbon steel will be base B=2.60 tons, percent of carbon in carbon steel is 1.15% i.e. R=1.15.

Putting these value in standard proportion,

  PB=R100P2.60=1.15100                           {Put B=2.60 and R=1.15}Applying cross multiplication,100P=1.15×2.60P=1.15×2.60100P=0.0299 tonsP=0.0299×2000                  {Since, 1 ton=2000 pound}P=59.8 pounds.

Hence, 59.8 pounds of carbon is required to make twist drill.

  2.Wrench :

As we know the proportion to find percentage is given as

  PB=R100   where, P=percentage, B= base and R=rate

Here, amount of carbon steel will be base B=2.60 tons, percent of carbon in carbon steel is 0.75% i.e. R=0.75.

Putting these value in standard proportion,

  PB=R100P2.60=0.75100                           {Put B=2.60 and R=0.75}Applying cross multiplication,100P=0.75×2.60P=0.75×2.60100P=0.0195 tonsP=0.0195×2000                  {Since, 1 ton=2000 pound}P=39 pounds.

Hence, 39 pounds of carbon is required to make wrench.

  3.Threading die :

As we know the proportion to find percentage is given as

  PB=R100   where, P=percentage, B= base and R=rate

Here, amount of carbon steel will be base B=2.60 tons, percent of carbon in carbon steel is 1.05% i.e. R=1.05.

Putting these value in standard proportion,

  PB=R100P2.60=1.05100                           {Put B=2.60 and R=1.05}Applying cross multiplication,100P=1.05×2.60P=1.05×2.60100P=0.0273 tonsP=0.0273×2000                  {Since, 1 ton=2000 pound}P=54.6 pounds.

Hence, 54.6 pounds of carbon is required to make threading die.

  4.Ordinary file :

As we know the proportion to find percentage is given as

  PB=R100   where, P=percentage, B= base and R=rate

Here, amount of carbon steel will be base B=2.60 tons, percent of carbon in carbon steel is 1.25% i.e. R=1.25.

Putting these value in standard proportion,

  PB=R100P2.60=1.25100                           {Put B=2.60 and R=1.25}Applying cross multiplication,100P=1.25×2.60P=1.25×2.60100P=0.0325 tonsP=0.0325×2000                  {Since, 1 ton=2000 pound}P=65 pounds.

Hence, 65 pounds of carbon is required to make ordinary file.

  5.Machinist's hammer :

As we know the proportion to find percentage is given as

  PB=R100   where, P=percentage, B= base and R=rate

Here, amount of carbon steel will be base B=2.60 tons, percent of carbon in carbon steel is 0.95% i.e. R=0.95.

Putting these value in standard proportion,

  PB=R100P2.60=0.95100                           {Put B=2.60 and R=0.95}Applying cross multiplication,100P=0.95×2.60P=0.95×2.60100P=0.0247 tonsP=0.0247×2000                  {Since, 1 ton=2000 pound}P=49.4 pounds.

Hence, 49.4 pounds of carbon is required to make Machinist's hammer.

  6.Chuck jaw :

As we know the proportion to find percentage is given as

  PB=R100   where, P=percentage, B= base and R=rate

Here, amount of carbon steel will be base B=2.60 tons, percent of carbon in carbon steel is 0.85% i.e. R=0.85.

Putting these value in standard proportion,

  PB=R100P2.60=0.85100                           {Put B=2.60 and R=0.85}Applying cross multiplication,100P=0.85×2.60P=0.85×2.60100P=0.0221 tonsP=0.0221×2000                  {Since, 1 ton=2000 pound}P=44.2 pounds.

Hence, 44.2 pounds of carbon is required to make Chuck jaw.

Therefore,

  59.8 pounds of carbon is required to make twist drill.

  39 pounds of carbon is required to make wrench.

  54.6 pounds of carbon is required to make threading die.

  65 pounds of carbon is required to make ordinary file.

  49.4 pounds of carbon is required to make Machinist's hammer.

  44.2 pounds of carbon is required to make Chuck jaw.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
2. In a computer network some pairs of computers are connected by network cables. Your goal is to set up the computers so that messages can be sent quickly from any computer to any other computer. For this you have identified each of the n com- puters uniquely with a number between 1 and n, and have decided that a message should consist of two such numbers, identifying the sender and the recipient, fol- lowed by the content of the message. As cables are relatively short, you can assume that sending a message across a single cable takes an amount of time that is the same irrespective of the length of the cable. You can further assume that at most one message travels between computer at any point, so that you don't have to worry about inference among messages. (a) Define a graph or network that models the computer network and allows you to answer the remaining parts of this question. (b) Consider two computers, a sender and a recipient. Using the graph or network you have defined,…
3. A spreadsheet consists of cells indexed by a row and a column. Each cell contains either a value or a formula that depends on the values of other cells. (a) Describe a graph, digraph, or network that models an arbitrary spreadsheet and allows you to answer the remaining parts of this question. (b) Explain, by referring to the graph, digraph, or network, when it is possible to change the value of cell x without changing the value of cell y. (c) Explain, by referring to the graph, digraph, or network, when it is possible to calculate the values of all cells in the spreadsheet. Consider the following spreadsheet with 5 rows, 7 columns, and 35 cells. For exam- ple, cell el contains a value, whereas cell al contains a formula that depends on the values cells el and 95. a b с 1 el+g5 al-c5 110 d al+cl 180 e f g f5-el c1+c2 2 al+b1 a2+c4 240 a2+c2 120 f5-e2 e3+e5 3 a2+b2 a3-c3 100 a3+c1 200 f5-e3 f1+f2 4 a3+b3 a4+c2 220 a4+c2 100 f5-e4 f3+f4 5 a4+b4 a5-c1 130 a5+c5 120 g3+g4 g1+g2 (d) Can…
1. Let W, U, and S be graphs defined as follows: • V(W) is the set of countries in the world; • V(U) is the set of countries in the European Union; V(S) is the set of countries in the Schengen Area; ● for X = {W,U,S}, E(X) is the set of pairs of countries in V(X) that share a land border. Recall that land borders between countries in the Schengen Area are special in that they can be crossed without a passport. (a) The notions of a country and a land border are somewhat ambiguous. Explain the notions you will use to get a precise definition of the graphs W, U, and S. (b) Is S a subgraph of U? Is U an induced subgraph of W? Justify your answers. (c) Using non-mathematical language, explain what it means for a country x if VEV(S) and dw (v) = 0. Give all such countries. Let A = {v Є V(W) \V(S) such that |Nw(v)| > 0 and Nw (v) ≤ V(S)}. (d) Using non-mathematical language, explain what the set A represents in terms of countries and land borders. Give a specific element of A or explain why A…

Chapter 24 Solutions

EBK MATHEMATICS FOR MACHINE TECHNOLOGY

Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Prob. 17ACh. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Prob. 21ACh. 24 - Prob. 22ACh. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Prob. 25ACh. 24 - Prob. 26ACh. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Prob. 31ACh. 24 - A manufacturer estimates that 15,500 pieces per...Ch. 24 - The average percent defective product of a...Ch. 24 - Prob. 34ACh. 24 - Prob. 35ACh. 24 - The cost of one dozen cutters is listed as $525. A...Ch. 24 - A manufacturer's production this week is 3620...Ch. 24 - Two machines are used to produce the same product....Ch. 24 - Allowing for scrap, a firm produced 1890 pieces....Ch. 24 - A manufacturing company receives $122,000 upon the...Ch. 24 - Prob. 41A
Knowledge Booster
Background pattern image
Advanced Math
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Mathematics For Machine Technology
Advanced Math
ISBN:9781337798310
Author:Peterson, John.
Publisher:Cengage Learning,
Text book image
Algebra: Structure And Method, Book 1
Algebra
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:McDougal Littell
Text book image
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Text book image
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Text book image
Elementary Geometry For College Students, 7e
Geometry
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Cengage,
Use of ALGEBRA in REAL LIFE; Author: Fast and Easy Maths !;https://www.youtube.com/watch?v=9_PbWFpvkDc;License: Standard YouTube License, CC-BY
Compound Interest Formula Explained, Investment, Monthly & Continuously, Word Problems, Algebra; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=P182Abv3fOk;License: Standard YouTube License, CC-BY
Applications of Algebra (Digit, Age, Work, Clock, Mixture and Rate Problems); Author: EngineerProf PH;https://www.youtube.com/watch?v=Y8aJ_wYCS2g;License: Standard YouTube License, CC-BY