EP ORGANIC CHEMISTRY -MOD.MASTERING 18W
EP ORGANIC CHEMISTRY -MOD.MASTERING 18W
9th Edition
ISBN: 9780136781776
Author: Wade
Publisher: PEARSON CO
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Chapter 24, Problem 24.47SP

(a)

Interpretation Introduction

Interpretation:

The structure of phenylalanine as it exists in D2O solution is to be stated.

Concept introduction:

The peaks in NMR spectrum are due to hydrogen atoms. Different signals are produced from different neighboring substituents of hydrogen atoms. Information about the structure of a compound is obtained by chemical shifts. Peaks due to aromatic protons occur between 78ppm.

(b)

Interpretation Introduction

Interpretation:

The peaks in the spectrum are to be assigned to the protons in the structure.

Concept introduction:

The peaks in NMR spectrum are due to hydrogen atoms. Different signals are produced from different neighboring substituents of hydrogen atoms. Information about the structure of a compound is obtained by chemical shifts. Peaks due to aromatic protons occur between 78ppm.

(c)

Interpretation Introduction

Interpretation:

The reason for the absence of NH2 or COOH protons in the spectrum is to be stated.

Concept introduction:

The peaks in NMR spectrum are due to hydrogen atoms. Different signals are produced from different neighboring substituents of hydrogen atoms. Information about the structure of a compound is obtained by chemical shifts. Peaks due to aromatic protons occur between 78ppm.

(d)

Interpretation Introduction

Interpretation:

The relationship between the two protons that generate nearly mirror-image multiplets at 3.1 and 3.3 is to be stated.

Concept introduction:

The peaks in NMR spectrum are due to hydrogen atoms. Different signals are produced from different neighbouring substituents of hydrogen atoms. Information about the structure of a compound is obtained by chemical shifts. Peaks due to aromatic protons occur between 78ppm.

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The emission data in cps displayed in Table 1 is reported to two decimal places by the chemist. However, the instrument output is shown in Table 2. Table 2. Iron emission from ICP-AES Sample Blank Standard Emission, cps 579.503252562 9308340.13122 Unknown Sample 343.232365741 Did the chemist make the correct choice in how they choose to display the data up in Table 1? Choose the best explanation from the choices below. No. Since the instrument calculates 12 digits for all values, they should all be kept and not truncated. Doing so would eliminate significant information. No. Since the instrument calculates 5 decimal places for the standard, all of the values should be limited to the same number. The other decimal places are not significant for the blank and unknown sample. Yes. The way Saman made the standards was limited by the 250-mL volumetric flask. This glassware can report values to 2 decimal places, and this establishes our number of significant figures. Yes. Instrumental data…

Chapter 24 Solutions

EP ORGANIC CHEMISTRY -MOD.MASTERING 18W

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