EP ORGANIC CHEMISTRY -MOD.MASTERING 18W
EP ORGANIC CHEMISTRY -MOD.MASTERING 18W
9th Edition
ISBN: 9780136781776
Author: Wade
Publisher: PEARSON CO
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Chapter 24, Problem 24.36SP
Interpretation Introduction

Interpretation: The structure for aspartame is to be determined.

Concept introduction: Aspartame is an artificial sweetener. It is approx 200 times as sweet as sugar and does not have the bitter aftertaste of stevia. So it has 200 times fewer calories. Aspartame is basically calorie-free.

To determine: The structure for aspartame.

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43) 10.00 ml of vinegar (active ingredient is acetic acid) is titrated to the endpoint using 19.32 ml of 0.250 M sodium hydroxide. What is the molarity of acetic acid in the vinegar? YOU MUST SHOW YOUR WORK. NOTE: MA x VA = MB x VB
424 Repon Sheet Rates of Chemical Reactions : Rate and Order of 1,0, Deception B. Effect of Temperature BATH TEMPERATURE 35'c Yol of Oh نام Time 485 Buret rend ing(n) 12 194 16. 6 18 20 10 22 24 14 115 95 14738 2158235 8:26 CMS 40148 Total volume of 0, collected Barometric pressure 770-572 ml mm Hg Vapor pressure of water at bath temperature (see Appendix L) 42.2 Slope Compared with the rate found for solution 1, there is Using the ideal gas law, calculate the moles of O; collected (show calculations) times faster 10 Based on the moles of O, evolved, calculate the molar concentration of the original 3% 1,0, solution (sho calculations)
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EP ORGANIC CHEMISTRY -MOD.MASTERING 18W

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