A constant potential difference of 12 v is maintained between the terminals of a 0.25- μ F, parallel-plate, air capacitor, (a) A sheet of Mylar is inserted between the plates of the capacitor, completely filling the space between the plates. When this is done, how much additional charge flows onto the positive plate of the capacitor (see Table 24.1)? (b) What is the total induced charge on cither face of the Mylar sheet? (c) What effect does the Mylar sheet have on the electric field between the plates? Explain how you can reconcile this with the increase in charge on the plates, which acts to increase the electric field.
A constant potential difference of 12 v is maintained between the terminals of a 0.25- μ F, parallel-plate, air capacitor, (a) A sheet of Mylar is inserted between the plates of the capacitor, completely filling the space between the plates. When this is done, how much additional charge flows onto the positive plate of the capacitor (see Table 24.1)? (b) What is the total induced charge on cither face of the Mylar sheet? (c) What effect does the Mylar sheet have on the electric field between the plates? Explain how you can reconcile this with the increase in charge on the plates, which acts to increase the electric field.
A constant potential difference of 12 v is maintained between the terminals of a 0.25-μF, parallel-plate, air capacitor, (a) A sheet of Mylar is inserted between the plates of the capacitor, completely filling the space between the plates. When this is done, how much additional charge flows onto the positive plate of the capacitor (see Table 24.1)? (b) What is the total induced charge on cither face of the Mylar sheet? (c) What effect does the Mylar sheet have on the electric field between the plates? Explain how you can reconcile this with the increase in charge on the plates, which acts to increase the electric field.
For a Teflon'M-filled, parallel-plate capacitor, the area of the plate is 52.0 cm2 and the spacing between the plates is 0.30 mm. If the capacitor is connected to a 210 V battery, find the following.
(a) the free charge on the capacitor plates (in nC)
nC
(b) the electrical field in the dielectric (in MV/m) (Enter the magnitude.)
MV/m
(c) the induced charge on the dielectric surfaces (in nC)
nc
If the electric field inside a capacitor exceeds thedielectric strength of the dielectric between its plates,the dielectric will break down, discharging andruining the capacitor. Thus, the dielectric strength isthe maximum magnitude that the electric field canhave without break-down occurring. The dielectricstrength of air is 3.0 x 10 V/m, and that of neoprenerubber is 1.2 x 10 V/m. A certain air-gap, parallelplate capacitor can store no more than 0.041 J ofelectrical energy before breaking down. How muchenergy can this capacitor store without breakingdown after the gap between its plates is filled withneoprene rubber? Take the dielectric constant of airto be 1.0, and of neoprene rubber to be 6.7.
(a)
What is the capacitance (in µF) of a parallel plate capacitor having plates of area 1.40 m2 that are separated by 0.0160 mm of Bakelite?
(b)
What charge (in µC) does it hold when 9.00 V is applied to it?
Chapter 24 Solutions
University Physics with Modern Physics (14th Edition)
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