In one type of computer keyboard, each key holds a small metal plate that serves as one plate of a parallel-plate, air-filled capacitor. When the key is depressed, the plate separation decreases and the capacitance increases. Electronic circuitry detects the change in capacitance and thus detects that the key has been pressed. In one particular keyboard, the area of each metal plate is 42.0 mm 2 , and the separation between the plates is 0.700 mm before the key is depressed, (a) Calculate the capacitance before the key is depressed, (b) If the circuitry can detect a change in capacitance of 0.250 pF, how far must the key be depressed before the circuitry detects its depression?
In one type of computer keyboard, each key holds a small metal plate that serves as one plate of a parallel-plate, air-filled capacitor. When the key is depressed, the plate separation decreases and the capacitance increases. Electronic circuitry detects the change in capacitance and thus detects that the key has been pressed. In one particular keyboard, the area of each metal plate is 42.0 mm 2 , and the separation between the plates is 0.700 mm before the key is depressed, (a) Calculate the capacitance before the key is depressed, (b) If the circuitry can detect a change in capacitance of 0.250 pF, how far must the key be depressed before the circuitry detects its depression?
In one type of computer keyboard, each key holds a small metal plate that serves as one plate of a parallel-plate, air-filled capacitor. When the key is depressed, the plate separation decreases and the capacitance increases. Electronic circuitry detects the change in capacitance and thus detects that the key has been pressed. In one particular keyboard, the area of each metal plate is 42.0 mm2, and the separation between the plates is 0.700 mm before the key is depressed, (a) Calculate the capacitance before the key is depressed, (b) If the circuitry can detect a change in capacitance of 0.250 pF, how far must the key be depressed before the circuitry detects its depression?
Will you please walk me through the calculations in more detail for solving this problem? I am a bit rusty on calculus and confused about the specific steps of the derivation: https://www.bartleby.com/solution-answer/chapter-3-problem-15e-modern-physics-2nd-edition/9780805303087/7cf8c31d-9476-46d5-a5a9-b897b16fe6fc
please help with the abstract. Abstract - This document outlines the format of the lab report and describes the Excel assignment. The abstract should be a short paragraph that very briefly includes the experiment objective, method, result and conclusion. After skimming the abstract, the reader should be able to decide whether they want to keep reading your work. Both the format of the report and the error analysis are to be followed. Note that abstract is not just the introduction and conclusion combined, but rather the whole experiment in short including the results. I have attacted the theory.
Using the Experimental Acceleration due to Gravity values from each data table, Data Tables 1, 2, and 3; determine the Standard Deviation, σ, mean, μ, variance, σ2 and the 95% Margin of Error (Confidence Level) Data: Ex. Acc. 1: 12.29 m/s^2. Ex. Acc. 2: 10.86 m/s^2, Ex. Acc. 3: 9.05 m/s^2
Chapter 24 Solutions
University Physics with Modern Physics (14th Edition)
Campbell Essential Biology with Physiology (5th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.