
Concept explainers
(a)
Interpretation:
The structure of all the
Concept introduction:
The simple sugars are monosaccharides having five or six carbon atoms as in fructose and glucose. At carbon
(b)
Interpretation:
The structure of an achiral ketopentose
Concept introduction:
A carbon atom is said to be chiral when all four atoms attached to it are different. It is also known as asymmetric carbon atom. Similarly when a molecule cannot be divided into two similar parts it is known as chiral or asymmetrical. When a molecule has a plane of symmetry, it is considered to be achiral. It means that molecule can be divided into two equal parts through the plane of symmetry.
(c)
Interpretation:
The structure of
Concept introduction:
Two isomers have same formula but different structures. In case of sugars, two isomers are possible on the basis of functional group present in the molecule. In pentose and hexose sugar they may be open ring structure with aldehyde group or close ring structures with keto group as main functional groups (keto, aldo isomers).
(d)
Interpretation:
The structure of
Concept introduction: Two isomers have same chemical formula but different structures. In case of sugars two isomers are possible on the basis of functional group present.( They may be open ring with aldehyde or close ring with keto group as their functional group.

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Chapter 24 Solutions
EBK ORGANIC CHEMISTRY
- 2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 H-CI CH2Cl2 CIarrow_forwardDraw the products of the stronger acid protonating the other reactant. དའི་སྐད”“ H3C OH H3C CH CH3 KEq Product acid Product basearrow_forwardDraw the products of the stronger acid protonating the other reactant. H3C NH2 NH2 KEq H3C-CH₂ 1. Product acid Product basearrow_forward
- What alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. draw structure ... andarrow_forwardDraw the products of the stronger acid protonating the other reactant. H3C-C=C-4 NH2 KEq CH H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 Br H-Br CH2Cl2 + enant.arrow_forward
- Draw the products of the stronger acid protonating the other reactant. KEq H₂C-O-H H3C OH Product acid Product basearrow_forwardDraw the products of the stronger acid protonating the other reactant. OH KEq CH H3C H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). Ph H-I CH2Cl2arrow_forward
- 3 attempts left Check my work Draw the products formed in the following oxidative cleavage. [1] 03 [2] H₂O draw structure ... lower mass product draw structure ... higher mass productarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). H-Br CH2Cl2arrow_forwardWrite the aldol condensation mechanism and product for benzaldehyde + cyclohexanone in a base. Then trans-cinnamaldehyde + acetone in base. Then, trans-cinnamaldehyde + cyclohexanone in a base.arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning


