Principles of Instrumental Analysis
7th Edition
ISBN: 9781305577213
Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher: Cengage Learning
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Chapter 24, Problem 24.12QAP
Interpretation Introduction
Interpretation:
A coulometric titration curve needs to be constructed containing 100.0 mL of a 1 M H2SO4 solution in which Fe(II) is titrated against Ce(IV) which is generated from 0.075 M Ce(III).
Concept introduction:
In coulometric titrations, a constant current is used to generate the titrant electro-analytically. In some coulometric titrations the analyte may be directly involved at the generator electrode. For example, the coulometric titration of Fe(II) in part by electro-analytically generated Ce(IV) and in part by direct electrode reaction.
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A weighed sample of sodium nitrite was treated with 0.05 mol of ceric sulfate in solution, in air-free conditions. The resulting solution was titrated with standard Fe(II) solution and 0.01 mol of Fe(II) were required. Determine the moles of sodium nitrite present in the weighed sample.
NO2– + 2 Ce4+ + H2O → NO3– + 2 Ce3+ + 2 H+ Fe2+ + Ce4+→ Fe3+ + Ce3+
1. A 0.8040 g sample of an iron ore is dissolved in acid. The iron is then reduced to Fe²+ and titrated
with 47.22 ml of 0.02242 M KMnO4 solution. Calculate the results of this analysis in terms of (a)
%Fe (MW = 55.845) and (b) %Fe3O4 (MW = 231.535). Consider the reaction
5 Fe²+ + MnO4 + 8H+ →
5Fe3+
+ Mn²+ + 4H₂O
Calculate the potential of the solution in the titration of 50.0 mL 0.100 M Fe2+ in 1.00 M HClO4 with 0.0167 M Cr2O72- at 10.00 mL titrant added.
Chapter 24 Solutions
Principles of Instrumental Analysis
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