To explain the statement “the hormone epinephrine generates a second messenger.” Concept introduction: Hormones are the special chemical messengers that are produced by glands in the living organisms. Hormones are responsible for the regulation of psychological activities and behavioral activities, such as metabolism , sleep, growth, and development. Glucose is a monosaccharide with the molecular formula C 6 H 12 O 6 . Glycogen is a polysaccharide of glucose. It serves as a form of carbohydrate storage in humans and animals. Glycogen is a source of glucose in humans and animals. Glycogenolysis is the metabolic pathway that converts glycogen to glucose 6 − phosphate . Epinephrine is a hormone that is released by adrenal glands. It promotes the release of glucose from glycogen and stimulates glycogenolysis, primarily in the muscle cells.

Question

Want to see the full answer?

Answer 1

Question

Chapter 24, Problem 24.113EP

Interpretation Introduction

Interpretation: To explain the statement “the hormone epinephrine generates a second messenger.”

Concept introduction: Hormones are the special chemical messengers that are produced by glands in the living organisms. Hormones are responsible for the regulation of psychological activities and behavioral activities, such as metabolism, sleep, growth, and development.

Glucose is a monosaccharide with the molecular formula C6H12O6. Glycogen is a polysaccharide of glucose. It serves as a form of carbohydrate storage in humans and animals. Glycogen is a source of glucose in humans and animals. Glycogenolysis is the metabolic pathway that converts glycogen to glucose 6−phosphate.

Epinephrine is a hormone that is released by adrenal glands. It promotes the release of glucose from glycogen and stimulates glycogenolysis, primarily in the muscle cells.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100

Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.

For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.