Automotive Technology
Automotive Technology
7th Edition
ISBN: 9781337794213
Author: ERJAVEC, Jack.
Publisher: Cengage,
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Chapter 24, Problem 1SA

Describe the difference between an open- and a closed-loop operation.

Expert Solution & Answer
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To determine

The difference between an open- and a closed-loop operation.

Answer to Problem 1SA

Closed-loop operations work on the principle of feedback. The output from the current operation is used to modify the input for the next operation. The open-loop operation works only on the input. There is no feedback for this open-loop operations.

Explanation of Solution

Some of the significant differences between an open- and a closed-loop operation are as follows:

Closed-loop operation Open-loop operation
Its basis is the output of the current operation. The feedback from the current output is used to modify the input. Does not have any feedback system. It completely works on the input.
Less stable. Mostly stables.
Overall cost is high. Overall cost is low.
Easy to calibrate. Difficult to calibrate.
Examples are refrigerator, Air conditioner, toaster, etc. Examples are automatic washing machine, Traffic light, TV remote, etc.
The structure of closed-loop operations are complex and so they are difficult to be implemented. The structure of open-loop operations are simple and so they are easy to be implemented.

Conclusion:

Closed-loop operation works on the feedback i.e. its basis is the output whereas open-loop operation is completely based on the input.

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6/86 The connecting rod AB of a certain internal-combustion engine weighs 1.2 lb with mass center at G and has a radius of gyration about G of 1.12 in. The piston and piston pin A together weigh 1.80 lb. The engine is running at a constant speed of 3000 rev/min, so that the angular velocity of the crank is 3000(2)/60 = 100л rad/sec. Neglect the weights of the components and the force exerted by the gas in the cylinder compared with the dynamic forces generated and calculate the magnitude of the force on the piston pin A for the crank angle 0 = 90°. (Suggestion: Use the alternative moment relation, Eq. 6/3, with B as the moment center.) Answer A = 347 lb 3" 1.3" B 1.7" PROBLEM 6/86
6/85 In a study of head injury against the instrument panel of a car during sudden or crash stops where lap belts without shoulder straps or airbags are used, the segmented human model shown in the figure is analyzed. The hip joint O is assumed to remain fixed relative to the car, and the torso above the hip is treated as a rigid body of mass m freely pivoted at O. The center of mass of the torso is at G with the initial position of OG taken as vertical. The radius of gyration of the torso about O is ko. If the car is brought to a sudden stop with a constant deceleration a, determine the speed v relative to the car with which the model's head strikes the instrument panel. Substitute the values m = 50 kg, 7 = 450 mm, r = 800 mm, ko = 550 mm, 0 = 45°, and a = 10g and compute v. Answer v = 11.73 m/s PROBLEM 6/85

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