How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro’s number of electrons from an initial point where the electric potential is 9.00 V to a point where the electric potential is −5.00 V? (The potential in each case is measured relative to a common reference point.)

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Answer 1

Textbook Question

Chapter 24, Problem 1P

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro’s number of electrons from an initial point where the electric potential is 9.00 V to a point where the electric potential is −5.00 V? (The potential in each case is measured relative to a common reference point.)

Expert Solution & Answer

To determine

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point.

Answer to Problem 1P

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

Explanation of Solution

Given information: Electric potential at initial point is 9.00 V and the electric potential at final point is −5.00 V , number of electron is equal to Avogadro’s number.

The expression for the work done is given as,

W=ΔV×Q (1)

The value of potential difference is calculated as,

ΔV=Vf−Vi

Substitute −5.00 V for Vf and 9.00 V for Vi in the above equation.

ΔV=Vf−Vi=−5.00 V−9.00 V=−14.00 V

The expression for the total charge is given as,

Q=ne

Here,

Q is total charge.

n is number of electrons.

e is the change of 1 electron.

Substitute 6.022×1023 for n and −1.6×10−19 C in the above equation.

Q=6.022×1023×−1.6×10−19 C=−96352 C

Substitute −96352 C for Q and −14.00 V for ΔV in the above equation.

W=−96352 C×(−14.00 V)=1348928 J=1.35 MJ

Conclusion:

Therefore, the work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

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Answer 2

Textbook Question

Chapter 24, Problem 1P

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro’s number of electrons from an initial point where the electric potential is 9.00 V to a point where the electric potential is −5.00 V? (The potential in each case is measured relative to a common reference point.)

Expert Solution & Answer

To determine

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point.

Answer to Problem 1P

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

Explanation of Solution

Given information: Electric potential at initial point is 9.00 V and the electric potential at final point is −5.00 V , number of electron is equal to Avogadro’s number.

The expression for the work done is given as,

W=ΔV×Q (1)

The value of potential difference is calculated as,

ΔV=Vf−Vi

Substitute −5.00 V for Vf and 9.00 V for Vi in the above equation.

ΔV=Vf−Vi=−5.00 V−9.00 V=−14.00 V

The expression for the total charge is given as,

Q=ne

Here,

Q is total charge.

n is number of electrons.

e is the change of 1 electron.

Substitute 6.022×1023 for n and −1.6×10−19 C in the above equation.

Q=6.022×1023×−1.6×10−19 C=−96352 C

Substitute −96352 C for Q and −14.00 V for ΔV in the above equation.

W=−96352 C×(−14.00 V)=1348928 J=1.35 MJ

Conclusion:

Therefore, the work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 24, Problem 1P

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro’s number of electrons from an initial point where the electric potential is 9.00 V to a point where the electric potential is −5.00 V? (The potential in each case is measured relative to a common reference point.)

Expert Solution & Answer

To determine

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point.

Answer to Problem 1P

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

Explanation of Solution

Given information: Electric potential at initial point is 9.00 V and the electric potential at final point is −5.00 V , number of electron is equal to Avogadro’s number.

The expression for the work done is given as,

W=ΔV×Q (1)

The value of potential difference is calculated as,

ΔV=Vf−Vi

Substitute −5.00 V for Vf and 9.00 V for Vi in the above equation.

ΔV=Vf−Vi=−5.00 V−9.00 V=−14.00 V

The expression for the total charge is given as,

Q=ne

Here,

Q is total charge.

n is number of electrons.

e is the change of 1 electron.

Substitute 6.022×1023 for n and −1.6×10−19 C in the above equation.

Q=6.022×1023×−1.6×10−19 C=−96352 C

Substitute −96352 C for Q and −14.00 V for ΔV in the above equation.

W=−96352 C×(−14.00 V)=1348928 J=1.35 MJ

Conclusion:

Therefore, the work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

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Answer 4

Textbook Question

Chapter 24, Problem 1P

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro’s number of electrons from an initial point where the electric potential is 9.00 V to a point where the electric potential is −5.00 V? (The potential in each case is measured relative to a common reference point.)

Expert Solution & Answer

To determine

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point.

Answer to Problem 1P

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

Explanation of Solution

Given information: Electric potential at initial point is 9.00 V and the electric potential at final point is −5.00 V , number of electron is equal to Avogadro’s number.

The expression for the work done is given as,

W=ΔV×Q (1)

The value of potential difference is calculated as,

ΔV=Vf−Vi

Substitute −5.00 V for Vf and 9.00 V for Vi in the above equation.

ΔV=Vf−Vi=−5.00 V−9.00 V=−14.00 V

The expression for the total charge is given as,

Q=ne

Here,

Q is total charge.

n is number of electrons.

e is the change of 1 electron.

Substitute 6.022×1023 for n and −1.6×10−19 C in the above equation.

Q=6.022×1023×−1.6×10−19 C=−96352 C

Substitute −96352 C for Q and −14.00 V for ΔV in the above equation.

W=−96352 C×(−14.00 V)=1348928 J=1.35 MJ

Conclusion:

Therefore, the work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point.

Answer to Problem 1P

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

Explanation of Solution

Given information: Electric potential at initial point is 9.00 V and the electric potential at final point is −5.00 V , number of electron is equal to Avogadro’s number.

The expression for the work done is given as,

W=ΔV×Q (1)

The value of potential difference is calculated as,

ΔV=Vf−Vi

Substitute −5.00 V for Vf and 9.00 V for Vi in the above equation.

ΔV=Vf−Vi=−5.00 V−9.00 V=−14.00 V

The expression for the total charge is given as,

Q=ne

Here,

Q is total charge.

n is number of electrons.

e is the change of 1 electron.

Substitute 6.022×1023 for n and −1.6×10−19 C in the above equation.

Q=6.022×1023×−1.6×10−19 C=−96352 C

Substitute −96352 C for Q and −14.00 V for ΔV in the above equation.

W=−96352 C×(−14.00 V)=1348928 J=1.35 MJ

Conclusion:

Therefore, the work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

Answer 8

Expert Solution & Answer

To determine

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point.

Answer to Problem 1P

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

Explanation of Solution

Given information: Electric potential at initial point is 9.00 V and the electric potential at final point is −5.00 V , number of electron is equal to Avogadro’s number.

The expression for the work done is given as,

W=ΔV×Q (1)

The value of potential difference is calculated as,

ΔV=Vf−Vi

Substitute −5.00 V for Vf and 9.00 V for Vi in the above equation.

ΔV=Vf−Vi=−5.00 V−9.00 V=−14.00 V

The expression for the total charge is given as,

Q=ne

Here,

Q is total charge.

n is number of electrons.

e is the change of 1 electron.

Substitute 6.022×1023 for n and −1.6×10−19 C in the above equation.

Q=6.022×1023×−1.6×10−19 C=−96352 C

Substitute −96352 C for Q and −14.00 V for ΔV in the above equation.

W=−96352 C×(−14.00 V)=1348928 J=1.35 MJ

Conclusion:

Therefore, the work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point.

Answer 12

Answer to Problem 1P

The work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .

Answer 13

Explanation of Solution

Given information: Electric potential at initial point is 9.00 V and the electric potential at final point is −5.00 V , number of electron is equal to Avogadro’s number.

The expression for the work done is given as,

W=ΔV×Q (1)

The value of potential difference is calculated as,

ΔV=Vf−Vi

Substitute −5.00 V for Vf and 9.00 V for Vi in the above equation.

ΔV=Vf−Vi=−5.00 V−9.00 V=−14.00 V

The expression for the total charge is given as,

Q=ne

Here,

Q is total charge.

n is number of electrons.

e is the change of 1 electron.

Substitute 6.022×1023 for n and −1.6×10−19 C in the above equation.

Q=6.022×1023×−1.6×10−19 C=−96352 C

Substitute −96352 C for Q and −14.00 V for ΔV in the above equation.

W=−96352 C×(−14.00 V)=1348928 J=1.35 MJ

Conclusion:

Therefore, the work done by the battery, generator, or some other source in moving Avogadro’s number of electron from an initial point to final point is 1.35 MJ .