The colour of the octahedral complexes such as CrX 6 3+ and CrY 6 3+ are being different. From this information, the stronger field ligand has to be found out among the neutral ligands X and Y . Concept Introduction: Strong field ligands: Gives larger splitting. So, splitting energy Δ o will be large. As a consequence electrons do not get transmitted to the higher energy level due to the large energy gap in between. So, remains paired up in the lower energy level. Thus, results in low-spin complexes . The wavelength of absorption corresponding to the large splitting energy Δ o will be of larger wavelength. Hence, the wavelength of absorption has a low frequency and lower energy. Weak field ligands: Gives smaller splitting. So, splitting energy Δ o will be small. As a consequence electrons will easily get transmitted to the higher energy level due to the small energy gap in between. So, remains unpaired by occupying the higher energy level. Thus, results in high-spin complexes . The wavelength of absorption corresponding to the small splitting energy Δ o will be of smaller wavelength. Hence, the wavelength of absorption has a high frequency and higher energy. So, if the colour of a given complex is of larger wavelength, then the complex is said to be a high-spin complex with the weak field ligand, since the larger wavelength gives the smallest splitting due to its smaller energy. In contrast, if the colour of a given complex is of smaller wavelength, then the complex is said to be a low-spin complex with the strong field ligand, since the smaller wavelength gives the largest splitting due to its greater energy.

Question

Want to see the full answer?

Answer 1

Question

Chapter 23.5, Problem 1RCF

Interpretation Introduction

Interpretation: The colour of the octahedral complexes such as $CrX63+$ and $CrY63+$ are being different. From this information, the stronger field ligand has to be found out among the neutral ligands $X$ and $Y$ .

Concept Introduction:

Strong field ligands:

Gives larger splitting.

So, $splitting energy Δo$ will be large.

As a consequence electrons do not get transmitted to the higher energy level due to the large energy gap in between. So, remains paired up in the lower energy level.

Thus, results in low-spin complexes.

The wavelength of absorption corresponding to the large $splitting energy Δo$ will be of larger wavelength.

Hence, the wavelength of absorption has a low frequency and lower energy.

Weak field ligands:

Gives smaller splitting.

So, $splitting energy Δo$ will be small.

As a consequence electrons will easily get transmitted to the higher energy level due to the small energy gap in between. So, remains unpaired by occupying the higher energy level.

Thus, results in high-spin complexes.

The wavelength of absorption corresponding to the small $splitting energy Δo$ will be of smaller wavelength.

Hence, the wavelength of absorption has a high frequency and higher energy.

So, if the colour of a given complex is of larger wavelength, then the complex is said to be a high-spin complex with the weak field ligand, since the larger wavelength gives the smallest splitting due to its smaller energy.

In contrast, if the colour of a given complex is of smaller wavelength, then the complex is said to be a low-spin complex with the strong field ligand, since the smaller wavelength gives the largest splitting due to its greater energy.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HO

b. H3C CH3 H3O+ ✓ H OH

2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3

Answer 2

Question

Chapter 23.5, Problem 1RCF

Interpretation Introduction

Interpretation: The colour of the octahedral complexes such as $CrX63+$ and $CrY63+$ are being different. From this information, the stronger field ligand has to be found out among the neutral ligands $X$ and $Y$ .

Concept Introduction:

Strong field ligands:

Gives larger splitting.

So, $splitting energy Δo$ will be large.

As a consequence electrons do not get transmitted to the higher energy level due to the large energy gap in between. So, remains paired up in the lower energy level.

Thus, results in low-spin complexes.

The wavelength of absorption corresponding to the large $splitting energy Δo$ will be of larger wavelength.

Hence, the wavelength of absorption has a low frequency and lower energy.

Weak field ligands:

Gives smaller splitting.

So, $splitting energy Δo$ will be small.

As a consequence electrons will easily get transmitted to the higher energy level due to the small energy gap in between. So, remains unpaired by occupying the higher energy level.

Thus, results in high-spin complexes.

The wavelength of absorption corresponding to the small $splitting energy Δo$ will be of smaller wavelength.

Hence, the wavelength of absorption has a high frequency and higher energy.

So, if the colour of a given complex is of larger wavelength, then the complex is said to be a high-spin complex with the weak field ligand, since the larger wavelength gives the smallest splitting due to its smaller energy.

In contrast, if the colour of a given complex is of smaller wavelength, then the complex is said to be a low-spin complex with the strong field ligand, since the smaller wavelength gives the largest splitting due to its greater energy.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 23.5, Problem 1RCF

Interpretation Introduction

Interpretation: The colour of the octahedral complexes such as $CrX63+$ and $CrY63+$ are being different. From this information, the stronger field ligand has to be found out among the neutral ligands $X$ and $Y$ .

Concept Introduction:

Strong field ligands:

Gives larger splitting.

So, $splitting energy Δo$ will be large.

As a consequence electrons do not get transmitted to the higher energy level due to the large energy gap in between. So, remains paired up in the lower energy level.

Thus, results in low-spin complexes.

The wavelength of absorption corresponding to the large $splitting energy Δo$ will be of larger wavelength.

Hence, the wavelength of absorption has a low frequency and lower energy.

Weak field ligands:

Gives smaller splitting.

So, $splitting energy Δo$ will be small.

As a consequence electrons will easily get transmitted to the higher energy level due to the small energy gap in between. So, remains unpaired by occupying the higher energy level.

Thus, results in high-spin complexes.

The wavelength of absorption corresponding to the small $splitting energy Δo$ will be of smaller wavelength.

Hence, the wavelength of absorption has a high frequency and higher energy.

So, if the colour of a given complex is of larger wavelength, then the complex is said to be a high-spin complex with the weak field ligand, since the larger wavelength gives the smallest splitting due to its smaller energy.

In contrast, if the colour of a given complex is of smaller wavelength, then the complex is said to be a low-spin complex with the strong field ligand, since the smaller wavelength gives the largest splitting due to its greater energy.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 23.5, Problem 1RCF

Interpretation Introduction

Interpretation: The colour of the octahedral complexes such as $CrX63+$ and $CrY63+$ are being different. From this information, the stronger field ligand has to be found out among the neutral ligands $X$ and $Y$ .

Concept Introduction:

Strong field ligands:

Gives larger splitting.

So, $splitting energy Δo$ will be large.

As a consequence electrons do not get transmitted to the higher energy level due to the large energy gap in between. So, remains paired up in the lower energy level.

Thus, results in low-spin complexes.

The wavelength of absorption corresponding to the large $splitting energy Δo$ will be of larger wavelength.

Hence, the wavelength of absorption has a low frequency and lower energy.

Weak field ligands:

Gives smaller splitting.

So, $splitting energy Δo$ will be small.

As a consequence electrons will easily get transmitted to the higher energy level due to the small energy gap in between. So, remains unpaired by occupying the higher energy level.

Thus, results in high-spin complexes.

The wavelength of absorption corresponding to the small $splitting energy Δo$ will be of smaller wavelength.

Hence, the wavelength of absorption has a high frequency and higher energy.

So, if the colour of a given complex is of larger wavelength, then the complex is said to be a high-spin complex with the weak field ligand, since the larger wavelength gives the smallest splitting due to its smaller energy.

In contrast, if the colour of a given complex is of smaller wavelength, then the complex is said to be a low-spin complex with the strong field ligand, since the smaller wavelength gives the largest splitting due to its greater energy.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 23.5, Problem 1RCF

Interpretation Introduction

Interpretation: The colour of the octahedral complexes such as $CrX63+$ and $CrY63+$ are being different. From this information, the stronger field ligand has to be found out among the neutral ligands $X$ and $Y$ .

Concept Introduction:

Strong field ligands:

Gives larger splitting.

So, $splitting energy Δo$ will be large.

As a consequence electrons do not get transmitted to the higher energy level due to the large energy gap in between. So, remains paired up in the lower energy level.

Thus, results in low-spin complexes.

The wavelength of absorption corresponding to the large $splitting energy Δo$ will be of larger wavelength.

Hence, the wavelength of absorption has a low frequency and lower energy.

Weak field ligands:

Gives smaller splitting.

So, $splitting energy Δo$ will be small.

As a consequence electrons will easily get transmitted to the higher energy level due to the small energy gap in between. So, remains unpaired by occupying the higher energy level.

Thus, results in high-spin complexes.

The wavelength of absorption corresponding to the small $splitting energy Δo$ will be of smaller wavelength.

Hence, the wavelength of absorption has a high frequency and higher energy.

So, if the colour of a given complex is of larger wavelength, then the complex is said to be a high-spin complex with the weak field ligand, since the larger wavelength gives the smallest splitting due to its smaller energy.

In contrast, if the colour of a given complex is of smaller wavelength, then the complex is said to be a low-spin complex with the strong field ligand, since the smaller wavelength gives the largest splitting due to its greater energy.

Answer 6

Chapter 23.5, Problem 1RCF

Interpretation Introduction

Interpretation: The colour of the octahedral complexes such as $CrX63+$ and $CrY63+$ are being different. From this information, the stronger field ligand has to be found out among the neutral ligands $X$ and $Y$ .

Concept Introduction:

Strong field ligands:

Gives larger splitting.

So, $splitting energy Δo$ will be large.

As a consequence electrons do not get transmitted to the higher energy level due to the large energy gap in between. So, remains paired up in the lower energy level.

Thus, results in low-spin complexes.

The wavelength of absorption corresponding to the large $splitting energy Δo$ will be of larger wavelength.

Hence, the wavelength of absorption has a low frequency and lower energy.

Weak field ligands:

Gives smaller splitting.

So, $splitting energy Δo$ will be small.

As a consequence electrons will easily get transmitted to the higher energy level due to the small energy gap in between. So, remains unpaired by occupying the higher energy level.

Thus, results in high-spin complexes.

The wavelength of absorption corresponding to the small $splitting energy Δo$ will be of smaller wavelength.

Hence, the wavelength of absorption has a high frequency and higher energy.

So, if the colour of a given complex is of larger wavelength, then the complex is said to be a high-spin complex with the weak field ligand, since the larger wavelength gives the smallest splitting due to its smaller energy.

In contrast, if the colour of a given complex is of smaller wavelength, then the complex is said to be a low-spin complex with the strong field ligand, since the smaller wavelength gives the largest splitting due to its greater energy.

Answer 7

Chapter 23.5, Problem 1RCF

Interpretation Introduction

Interpretation: The colour of the octahedral complexes such as $CrX63+$ and $CrY63+$ are being different. From this information, the stronger field ligand has to be found out among the neutral ligands $X$ and $Y$ .

Concept Introduction:

Strong field ligands:

Gives larger splitting.

So, $splitting energy Δo$ will be large.

As a consequence electrons do not get transmitted to the higher energy level due to the large energy gap in between. So, remains paired up in the lower energy level.

Thus, results in low-spin complexes.

The wavelength of absorption corresponding to the large $splitting energy Δo$ will be of larger wavelength.

Hence, the wavelength of absorption has a low frequency and lower energy.

Weak field ligands:

Gives smaller splitting.

So, $splitting energy Δo$ will be small.

As a consequence electrons will easily get transmitted to the higher energy level due to the small energy gap in between. So, remains unpaired by occupying the higher energy level.

Thus, results in high-spin complexes.

The wavelength of absorption corresponding to the small $splitting energy Δo$ will be of smaller wavelength.

Hence, the wavelength of absorption has a high frequency and higher energy.

So, if the colour of a given complex is of larger wavelength, then the complex is said to be a high-spin complex with the weak field ligand, since the larger wavelength gives the smallest splitting due to its smaller energy.

In contrast, if the colour of a given complex is of smaller wavelength, then the complex is said to be a low-spin complex with the strong field ligand, since the smaller wavelength gives the largest splitting due to its greater energy.

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 23.1 - Identify the following transition metal atoms and...Ch. 23.3 - Write the oxidation numbers of the metals in the...Ch. 23.3 - Prob. 2PE Ch. 23.3 - Prob. 3PE Ch. 23.3 - Prob. 1RCF Ch. 23.3 - What is the difference between these two...Ch. 23.3 - Prob. 3RCF Ch. 23.4 - Prob. 1RCF Ch. 23.5 - Prob. 4PE Ch. 23.5 - Prob. 1RCF

Concept explainers

Videos

Want to see the full answer?

Chapter 23 Solutions