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(a)
Interpretation: Using a Gabriel synthesis, a give set of primary amine compounds have to be synthesized.
Concept Introduction: The general formula for primary amine is –NH2. There are several methods available to prepare primary
Step-1: Formation of potassium phthalimide (deprotonation)
Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.
Step-2: Formation of R−N bond by SN2 nucleophilic substitution
The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary
Step-3: Formation of primary amine by hydrolysis
The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.
(b)
Interpretation: Using a Gabriel synthesis, a give set of primary amine compounds have to be synthesized.
Concept Introduction: The general formula for primary amine is –NH2. There are several methods available to prepare primary amines. Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps.
Step-1: Formation of potassium phthalimide (deprotonation)
Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.
Step-2: Formation of R−N bond by SN2 nucleophilic substitution
The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is SN2 nucleophilic substitution reaction. Halogen atom is going away as halide anion.
Step-3: Formation of primary amine by hydrolysis
The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.
(c)
Interpretation: Using a Gabriel synthesis, a give set of primary amine compounds have to be synthesized.
Concept Introduction: The general formula for primary amine is –NH2. There are several methods available to prepare primary amines. Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps.
Step-1: Formation of potassium phthalimide (deprotonation)
Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.
Step-2: Formation of R−N bond by SN2 nucleophilic substitution
The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is SN2 nucleophilic substitution reaction. Halogen atom is going away as halide anion.
Step-3: Formation of primary amine by hydrolysis
The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.
(d)
Interpretation: Using a Gabriel synthesis, a give set of primary amine compounds have to be synthesized.
Concept Introduction: The general formula for primary amine is –NH2. There are several methods available to prepare primary amines. Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps.
Step-1: Formation of potassium phthalimide (deprotonation)
Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.
Step-2: Formation of R−N bond by SN2 nucleophilic substitution
The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is SN2 nucleophilic substitution reaction. Halogen atom is going away as halide anion.
Step-3: Formation of primary amine by hydrolysis
The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.
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Chapter 23 Solutions
Student Study Guide and Solutions Manual T/A Organic Chemistry
- H HgSO4, H2O H2SO4arrow_forward12. Choose the best diene and dienophile pair that would react the fastest. CN CN CO₂Et -CO₂Et .CO₂Et H3CO CO₂Et A B C D E Farrow_forward(6 pts - 2 pts each part) Although we focused our discussion on hydrogen light emission, all elements have distinctive emission spectra. Sodium (Na) is famous for its spectrum being dominated by two yellow emission lines at 589.0 and 589.6 nm, respectively. These lines result from electrons relaxing to the 3s subshell. a. What is the photon energy (in J) for one of these emission lines? Show your work. b. To what electronic transition in hydrogen is this photon energy closest to? Justify your answer-you shouldn't need to do numerical calculations. c. Consider the 3s subshell energy for Na - use 0 eV as the reference point for n=∞. What is the energy of the subshell that the electron relaxes from? Choose the same emission line that you did for part (a) and show your work.arrow_forward
- Nonearrow_forward(9 Pts) In one of the two Rare Earth element rows of the periodic table, identify an exception to the general ionization energy (IE) trend. For the two elements involved, answer the following questions. Be sure to cite sources for all physical data that you use. a. (2 pts) Identify the two elements and write their electronic configurations. b. (2 pts) Based on their configurations, propose a reason for the IE trend exception. c. (5 pts) Calculate effective nuclear charges for the last electron in each element and the Allred-Rochow electronegativity values for the two elements. Can any of these values explain the IE trend exception? Explain how (not) - include a description of how IE relates to electronegativity.arrow_forwardPlease explain thoroughly and provide steps to draw.arrow_forward
- As you can see in the picture, the instrument uses a Xe source. Given that the instrument is capable of measuring from 200-800nm, if Xe was not used, what other source(s) could be used? Refer to figure 7-3. How many monochrometers does this instrument have? Why? Trace the light as it goes from the Xenon lamp all the way to the circle just slightly to the right and a little bit down from S4. What do you think that circle is? In class we talked about many types of these, which kind do you think this one is for a fluorimeter? Why? Explain. What is/are some strategy(ies) that this instrument has for dealing with noise that you see present in the optics diagram? Why does a fluorescence cuvette have to be clear on four sides?arrow_forwardProvide steps and thoroughly solve.arrow_forwardNonearrow_forward
- Devise a synthesis to prepare 4-tert-butyl-2-nitrotoluene from toluene. Complete the following reaction scheme. Part 1 of 4 Step 1 Step 2 A B Draw the structure for compound B, 4-tert-butyl-2-nitrotoluene. Click and drag to start drawing a structure. 'O Х ப:arrow_forwardWhat is N hybridized? sp3 or sp2? whyarrow_forwardDate Unknown o Hydrated Salt Lab Sec. Name Trial I Trial 2 1. Mass of fired crucible and lid (g) 2. Mass of fired crucible, lid, and hydrated sah (g) 3. Instructor's approval of flame and apparatus 4. Mass of crucible, lid, and anhydrous salt Ist mass measurement (g) 2nd mass measurement (g) 3rd mass measurement (g). Desk No. Trial 3 48.833 46.808 213.692 51.507 9.359 46,615 50.296 48.211 45.351 50.142 48.146 45.1911 50.103 48.132 45.186 5. Final mass of crucible, lid, and anhydrous salt (g) 50.180 4.13 45.243 Calculations 1. Mass of hydrated salt (g) 2. Mass of anhydrous salt (g) 2.674 2.491 2.9239 1.3479 1.2959 1.5519 3. Mass of water lost (g) 1.32791969 1.322g 4. Percent by mass of volatile water in hydrated salt (%) 49.6% 48% 216.9% 5. Average percent HO in bydrated salt (%H,O) 5. Standard deviation of %H,O Relative standard deviation of %H,O in hydrated salt (RSD) how calculations on next page. 48.17% Data Analysis, B Data Analysis, C Data Analysis, D Experiment 5 89arrow_forward
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