Explanation Given Information: Function is given as f ( x ) = 3 x x 2 − x To find the suspicious point, taking denominator, and putting it equal to 0, x 2 − x = 0 ⇒ x ( x − 1 )

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 2.3, Problem 9PS

To determine

The suspicious points and all the discontinuity points.

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Chapter 2.3, Problem 8PS

Chapter 2.3, Problem 10PS

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Chapter 2 Solutions

Calculus

Ch. 2.1 - Prob. 1PS Ch. 2.1 - Prob. 2PS Ch. 2.1 - Prob. 3PS Ch. 2.1 - Prob. 4PS Ch. 2.1 - Prob. 5PS Ch. 2.1 - Prob. 6PS Ch. 2.1 - Prob. 7PS Ch. 2.1 - Prob. 8PS Ch. 2.1 - Prob. 9PS Ch. 2.1 - Prob. 10PS

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The suspicious points and all the discontinuity points.

Solution Summary: The author explains that the suspicious points and all the discontinuity points are 0. Removable and Infinite discontinuities at x = 1.

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The suspicious points and all the discontinuity points.

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Chapter 2 Solutions