Explanation Given: The record is given below: Time t 2:50 2:55 2:59 3:00 3:01 3:01 3:06 Odometer reading 33.9 38.2 41.5 42.4 43.2 44.9 47.4 Formula used: Average velocity: v a v g = x 2 − x 1 t 2 − t 1 Calculation: In the first interval: 2.50 to 2.55 has t = 5 min. v a v g = 38.2 − 33.9 5 = 4.3 5 = 0.86 mi/min = 51 .6 mi/hr In the second interval: 2.55 to 2.59 has t = 4 min. v a v g = 41.5 − 38.2 4 = 3.3 4 = 0.825 mi/min = 49. 5 mi/hr In the third interval: 2.59 to 3.00 has t = 1 min. v a v g = 42.4 − 41.5 1 = 0

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 2.1, Problem 50PS

To determine

To estimate:The velocity at 3.00 P.M.

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Chapter 2.1, Problem 49PS

Chapter 2.1, Problem 51PS

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Chapter 2 Solutions

Calculus

Ch. 2.1 - Prob. 1PS Ch. 2.1 - Prob. 2PS Ch. 2.1 - Prob. 3PS Ch. 2.1 - Prob. 4PS Ch. 2.1 - Prob. 5PS Ch. 2.1 - Prob. 6PS Ch. 2.1 - Prob. 7PS Ch. 2.1 - Prob. 8PS Ch. 2.1 - Prob. 9PS Ch. 2.1 - Prob. 10PS

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To estimate: The velocity at 3.00 P.M.

Solution Summary: The author explains the formula used to estimate the velocity at 3.00 P.M. The instantaneous velocity is 51 mi/hr.

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To estimate:The velocity at 3.00 P.M.

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Chapter 2 Solutions