Explanation Given: The given limit is lim x → 1 + 1 x − 3 Concept Used: The limit lim x → c + f ( x ) is equals to L , if we can make the number f ( x ) as close to L as we please by choosing x sufficiently close to c on an interval ( c , b ) immediately to the right of c Calculation: In order to evaluate the limit lim x → 1 + 1 x − 3 Let’s form a table of values of f ( x ) = 1 x − 3 , choosing values of x sufficiently close to 1, say 1.2 , 1.1 , 1.01 , and 1.001 on interval ( 1 , b ) for any positive real value b Since, f ( 1.2 ) = 1 1.2 − 3 = − 1 1.8 , f ( 1.1 ) = 1 1.1 − 3 = − 1 1.9 , f ( 1.01 ) = 1 1.01 − 3 = − 1 1

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Chapter 2.1, Problem 25PS

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To evaluate the given limit.

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Chapter 2.1, Problem 24PS

Chapter 2.1, Problem 26PS

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Chapter 2 Solutions

Calculus

Ch. 2.1 - Prob. 1PS Ch. 2.1 - Prob. 2PS Ch. 2.1 - Prob. 3PS Ch. 2.1 - Prob. 4PS Ch. 2.1 - Prob. 5PS Ch. 2.1 - Prob. 6PS Ch. 2.1 - Prob. 7PS Ch. 2.1 - Prob. 8PS Ch. 2.1 - Prob. 9PS Ch. 2.1 - Prob. 10PS

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To evaluate the given limit.

Solution Summary: The author explains that the given limit is limxc+f(x) equals to L, if we can make the number as close as we please by choosing values of x sufficiently close to 1, say 1.2

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To evaluate the given limit.

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Chapter 2 Solutions