Chemistry: The Central Science (14th Edition)
Chemistry: The Central Science (14th Edition)
14th Edition
ISBN: 9780134414232
Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus
Publisher: PEARSON
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Chapter 23, Problem 86AE
Interpretation Introduction

Interpretation:

At octahedral sites in the close packed oxide lattice of Al2O3, the color of ruby being red due to the presence of Cr(III) is given. The crystal field splitting diagram of Cr(III) in the given environment, the variation of pressure in ruby crystal as a function of wavelength are to be determined.

Concept introduction:

A model that depicts the breakage of the degeneracies of the electron orbital states because of a static electric field is known as crystal field theory. The static field is produced by the surrounding charge distribution.

Crystal field theory is based on the degeneracy of d-orbitals when they come in contact with the ligand.

To determine:

The crystal field diagram of Cr(III) and the variation of wavelength as a function of pressure.

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Chapter 23 Solutions

Chemistry: The Central Science (14th Edition)

Ch. 23.5 - Prob. 23.6.1PECh. 23.5 - Prob. 23.6.2PECh. 23.6 - Prob. 23.7.1PECh. 23.6 - Prob. 23.7.2PECh. 23.6 - Prob. 23.8.1PECh. 23.6 - Prob. 23.8.2PECh. 23 - Prob. 1DECh. 23 - The three graphs below show the variation in...Ch. 23 - Prob. 2ECh. 23 - Prob. 3ECh. 23 - Prob. 4ECh. 23 - Prob. 5ECh. 23 - Prob. 6ECh. 23 - Prob. 7ECh. 23 - Prob. 8ECh. 23 - Prob. 9ECh. 23 - Prob. 10ECh. 23 - Prob. 11ECh. 23 - Prob. 12ECh. 23 - Prob. 13ECh. 23 - Prob. 14ECh. 23 - Write out the ground-state electron configurations...Ch. 23 - Prob. 16ECh. 23 - Prob. 17ECh. 23 - Prob. 18ECh. 23 - Prob. 19ECh. 23 - Prob. 20ECh. 23 - Prob. 21ECh. 23 - Prob. 22ECh. 23 - Prob. 23ECh. 23 - Prob. 24ECh. 23 - Prob. 25ECh. 23 - Indicate the coordination number and the oxidation...Ch. 23 - Prob. 27ECh. 23 - Prob. 28ECh. 23 - Prob. 29ECh. 23 - Prob. 30ECh. 23 - Prob. 31ECh. 23 - Prob. 32ECh. 23 - Prob. 33ECh. 23 - Prob. 34ECh. 23 - Write the formula for each of the following...Ch. 23 - Prob. 36ECh. 23 - Prob. 37ECh. 23 - Prob. 38ECh. 23 - Prob. 39ECh. 23 - Prob. 40ECh. 23 - Prob. 41ECh. 23 - Prob. 42ECh. 23 - Prob. 43ECh. 23 - Prob. 44ECh. 23 - Prob. 45ECh. 23 - Prob. 46ECh. 23 - Prob. 47ECh. 23 - Prob. 48ECh. 23 - Prob. 49ECh. 23 - Prob. 50ECh. 23 - Prob. 51ECh. 23 - Prob. 52ECh. 23 - 23.53 Sketch a diagram that shows the definition...Ch. 23 - Prob. 54ECh. 23 - Prob. 55ECh. 23 - Prob. 56ECh. 23 - Prob. 57ECh. 23 - Prob. 58ECh. 23 - Prob. 59ECh. 23 - Prob. 60ECh. 23 - Prob. 61ECh. 23 - 23.62 For each of the following metals, write the...Ch. 23 - Prob. 63ECh. 23 - Prob. 64ECh. 23 - Prob. 65ECh. 23 - Prob. 66ECh. 23 - Prob. 67AECh. 23 - Prob. 68AECh. 23 - Prob. 69AECh. 23 - Prob. 70AECh. 23 - Prob. 71AECh. 23 - Prob. 72AECh. 23 - Prob. 73AECh. 23 - Prob. 74AECh. 23 - Prob. 75AECh. 23 - Prob. 76AECh. 23 - Prob. 77AECh. 23 - Prob. 78AECh. 23 - Prob. 79AECh. 23 - Prob. 80AECh. 23 - Prob. 81AECh. 23 - Prob. 82AECh. 23 - Oxyhemoglobin, with an O2 bound to iron, is a...Ch. 23 - Prob. 84AECh. 23 - Prob. 85AECh. 23 - Prob. 86AECh. 23 - Prob. 87AECh. 23 - Prob. 88AECh. 23 - Prob. 89AECh. 23 - Prob. 90AECh. 23 - Prob. 91AECh. 23 - Prob. 92IECh. 23 - Prob. 93IECh. 23 - Prob. 94IECh. 23 - Prob. 95IECh. 23 - Prob. 96IECh. 23 - Prob. 97IECh. 23 - Prob. 98IECh. 23 - Prob. 99IECh. 23 - Prob. 100IECh. 23 - Prob. 101IE
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