Explanation Given: Mass of coal is 1.00 × 10 2 kg . Explanation: During the combustion of lignite and bituminous coal, sulfur content comes out, which reacts with oxygen to form sulfur dioxide. Sulfur dioxide reacts with water in the atmosphere and forms sulfuric acid. The related chemical reactions are given as follows: S + O 2 → SO 2 2 SO 2 + O 2 + 2 H 2 O → 2 H 2 SO 4 To obtain the mass of sulfuric acid formed by burning 1.00 × 10 2 kg of coal (lignite or bituminous), calculate the amount of sulfur in it using the sulfur content or corresponding the type of coal. Then, convert the mass of S into moles of S. Later, convert the moles of S into SO 2 and then followed to H 2 SO 4 , the formula that is used in the reactions. Finally, calculate the mass of H 2 SO 4 from the moles and the molar mass used. Calculate the mass of sulfur in 1.00 × 10 2 kg of lignite. Calculate the ratio of mass of S to empirical formula mass of lignite as follows: Ratio = Atomic mass of sulfur Molecular mass of C 71 H 4 O 23 S = 32.06 g/mol 1344.6 g/mol = 0.0238 The empirical formula form of lignite composition is C 71 H 4 O 23 S . Mass of sulfuric acid = ( Mass of lignite Atomic mass of sulfur ) × ( Mass of sulfur 100 kg of lignite coal ) × ( 1 mol SO 2 1 mol S ) × ( 2 mol H 2 SO 4 2 mol SO 2 ) × ( Molar mass of H 2 SO 4 ) = ( 1.00 × 10 2 kg 32.06 g/mol ) × ( 2

Chemistry: A Molecular Approach (4th Edition)

4th Edition

ISBN: 9780134112831

Author: Nivaldo J. Tro

Publisher: PEARSON

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Group 15 elements

The elements of group 15 are phosphorus, nitrogen, bismuth antimony, and arsenic. The most abundant element which is present in the air is nitrogen and the percentage of nitrogen present in the air is 78%. In the free state, the elemental nitrogen is pre…

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Chapter 23, Problem 77E

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To calculate: The mass of sulfuric acid.

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Chapter 23, Problem 76E

Chapter 23, Problem 78E

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Chemistry: A Molecular Approach (4th Edition)

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