
Concept explainers
(a)
Write an equation that represent the situation and find the cost of potatoes.
(a)

Answer to Problem 52PPS
Explanation of Solution
Given:
The cost of a bag of potatoes is $1.50 less than
Concept Used:
At first convert the condition given in the question into an algebraic equation.
Let the cost of a bag of potato is
The cost of a bag of potatoes is $1.50 less than
Equation:
Calculation:
As given in the chart: The cost of Apple is $6.99 per bag
Equation:
Now plug in the value of
Find the cost of 1 bag potato:
Cost of 1 bag potato is $2
Thus, the cost of 1 bag potato is $2.
(b)
Write and solve an equation to find the cost of zucchini.
(b)

Answer to Problem 52PPS
Explanation of Solution
Given:
Condition:The price of each zucchini is 3 times the price of winter squash minus $7
Concept Used:
At first we need to convert the condition given in the question into an equation.
Let the cost of each zucchini is
The price of each zucchini is 3 times the price of winter squash minus $7
Equation:
Calculation:
According to the chart given in the question theCost of winter squash 2.99 each
Equation:
To find the cost of each zucchini, plug in the value of squash:
Find the cost of each zucchini:
The cost of each zucchini is
Thus, the cost of each zucchini is
(c)
Write an equation to represent the cost of a pumpkin using the cost of blue barriers.
(c)

Answer to Problem 52PPS
Explanation of Solution
Given:
Cost of Pumpkin - $5.00 each and Blue barriers − 2.99 per quartz.
Concept Used:
We need to write an equation to represent the cost of a pumpkin using the cost of blue barriers.
In the question it is given that Cost of Pumpkin - $5.00 each and Blue barriers − 2.99 per quartz
Let the Cost of each Pumpkin is
Calculation:
In the question it is given that Cost of Pumpkin - $5.00 each and Blue barriers − 2.99 per quartz
The cost of a pumpkin in terms of the cost of blue barriers is:
Equation:
Thus, the cost of pumpkin in terms of the cost blue barriers
Chapter 2 Solutions
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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