ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT
ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT
2nd Edition
ISBN: 9781119288510
Author: Klein
Publisher: WILEY
Question
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Chapter 23, Problem 41PP

(a)

Interpretation Introduction

Interpretation: The stronger base has to be identified in the given pair of compounds

Concept Introduction:

If the lone pair of electrons on nitrogen atom in amine compound is delocalized, that compound is resonance stabilized.  It is also involved in aromatic stabilization.  As a result, a number of resonance structures are drawn for the delocalization of electrons in the structures.  So, the compound has less basic character.  If the lone pair of electrons on nitrogen atom in amine compound is localized, that compound doesn’t involve in resonance stabilization.  So, that compound has more basic character.  sp3 hybridized nitrogen atom is expected to function as more basic character than sp2 hybridized nitrogen atom which has again basic character than sp hybridized nitrogen atom.

To find: Identify the stronger base in the given pair of compounds (a)

Find the behavior of nitrogen atom in pyridine

(b)

Interpretation Introduction

Interpretation: The stronger base has to be identified in the given pair of compounds

Concept Introduction:

If the lone pair of electrons on nitrogen atom in amine compound is delocalized, that compound is resonance stabilized.  It is also involved in aromatic stabilization.  As a result, a number of resonance structures are drawn for the delocalization of electrons in the structures.  So, the compound has less basic character.  If the lone pair of electrons on nitrogen atom in amine compound is localized, that compound doesn’t involve in resonance stabilization.  So, that compound has more basic character.  sp3 hybridized nitrogen atom is expected to function as more basic character than sp2 hybridized nitrogen atom which has again basic character than sp hybridized nitrogen atom.

To find: Identify the stronger base in the given pair of compounds (b)

Find the behavior of nitrogen atom in an amide group

(c)

Interpretation Introduction

Interpretation: The stronger base has to be identified in the given pair of compounds

Concept Introduction:

If the lone pair of electrons on nitrogen atom in amine compound is delocalized, that compound is resonance stabilized.  It is also involved in aromatic stabilization.  As a result, a number of resonance structures are drawn for the delocalization of electrons in the structures.  So, the compound has less basic character.  If the lone pair of electrons on nitrogen atom in amine compound is localized, that compound doesn’t involve in resonance stabilization.  So, that compound has more basic character.  sp3 hybridized nitrogen atom is expected to function as more basic character than sp2 hybridized nitrogen atom which has again basic character than sp hybridized nitrogen atom.

To find: Identify the stronger base in the given pair of compounds (c)

Find the behavior of nitrogen atom in five-membered ring

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3. SYNTHESIS. Propose a sequence of synthetic steps (FGI) that convert the starting material (SM) into the Target molecule. For each FGI in your proposed synthesis, specify the reagents / conditions, and draw the product(s) of that FGI. DO NOT INCLUDE the FGI mxn in the answer you submit. If an FGI requires two reagent sets, specify the order in which the reagent sets are added, e.g., i) Hg(OAc)2 / H₂O; ii) NaBH4/MeOH. Indicate the stereochemistry (if any) of the products of each FGI. FGI 1. Me Starting Material Source of all carbons in the Target molecule (can use multiple copies) Me Me Target molecule + enantiomer
curved arrows are used to illustate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction mechanism steps

Chapter 23 Solutions

ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT

Ch. 23.4 - Prob. 10CCCh. 23.4 - Prob. 11CCCh. 23.5 - Prob. 2LTSCh. 23.5 - Prob. 12PTSCh. 23.5 - Prob. 13PTSCh. 23.6 - Prob. 3LTSCh. 23.6 - Prob. 14PTSCh. 23.6 - Prob. 15ATSCh. 23.6 - Prob. 16ATSCh. 23.6 - Prob. 17ATSCh. 23.7 - Prob. 18PTSCh. 23.7 - Prob. 19PTSCh. 23.7 - Prob. 20PTSCh. 23.7 - Prob. 21ATSCh. 23.8 - Prob. 22CCCh. 23.8 - Prob. 23CCCh. 23.8 - Prob. 24CCCh. 23.9 - Prob. 5LTSCh. 23.9 - Prob. 25PTSCh. 23.9 - Prob. 26ATSCh. 23.9 - Prob. 27ATSCh. 23.9 - Prob. 28ATSCh. 23.10 - Prob. 29CCCh. 23.11 - Prob. 30CCCh. 23.11 - Prob. 6LTSCh. 23.11 - Prob. 31PTSCh. 23.11 - Prob. 32ATSCh. 23.11 - Prob. 33ATSCh. 23.12 - Prob. 34CCCh. 23.12 - Prob. 35CCCh. 23.13 - Prob. 36CCCh. 23.13 - Prob. 37CCCh. 23 - Prob. 38PPCh. 23 - Prob. 39PPCh. 23 - Prob. 40PPCh. 23 - Prob. 41PPCh. 23 - Prob. 42PPCh. 23 - Prob. 43PPCh. 23 - Prob. 44PPCh. 23 - Prob. 45PPCh. 23 - Prob. 46PPCh. 23 - Prob. 47PPCh. 23 - Prob. 48PPCh. 23 - Prob. 49PPCh. 23 - Prob. 50PPCh. 23 - Prob. 51PPCh. 23 - Prob. 52PPCh. 23 - Prob. 53PPCh. 23 - Prob. 54PPCh. 23 - Prob. 55PPCh. 23 - Prob. 56PPCh. 23 - Prob. 57PPCh. 23 - Prob. 58PPCh. 23 - Prob. 59PPCh. 23 - Prob. 60PPCh. 23 - Prob. 61PPCh. 23 - Prob. 62PPCh. 23 - Prob. 63PPCh. 23 - Prob. 64PPCh. 23 - Prob. 65PPCh. 23 - Prob. 66PPCh. 23 - Prob. 67PPCh. 23 - Prob. 68PPCh. 23 - Prob. 69PPCh. 23 - Prob. 70PPCh. 23 - Prob. 71PPCh. 23 - Prob. 72PPCh. 23 - Prob. 73PPCh. 23 - Prob. 74PPCh. 23 - Prob. 75PPCh. 23 - Prob. 76PPCh. 23 - Prob. 77IPCh. 23 - Prob. 78IPCh. 23 - Prob. 79IPCh. 23 - Prob. 80IPCh. 23 - Prob. 81IPCh. 23 - Prob. 82IPCh. 23 - Prob. 83IPCh. 23 - Prob. 84IPCh. 23 - Prob. 85IPCh. 23 - Prob. 86IPCh. 23 - Prob. 87IPCh. 23 - Prob. 88IPCh. 23 - Prob. 89IPCh. 23 - Prob. 90IPCh. 23 - Prob. 91CPCh. 23 - Prob. 92CPCh. 23 - Prob. 93CPCh. 23 - Prob. 94CPCh. 23 - Prob. 95CPCh. 23 - Prob. 96CPCh. 23 - Prob. 97CPCh. 23 - Prob. 98CP
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