EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 9780100793439
Author: KALPAKJIAN
Publisher: YUZU
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Chapter 23, Problem 35QLP
The operational severity for reaming is much lower than that for tapping, even though they both are internal machining processes. Why?
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Students have asked these similar questions
Determine the total machining time for a workpiece 30mm in diameter and the
required length is 145 mm. Other data:
Material: 38mm dia. X 149 mm
Depth of cut (turning): 4mm
Depth of cut (facing): 2mm
Feed
: 0.05 mm/rev
: 35 SMPM
Cutting speed
In an orthogonal machining with a tool of 9
orthogonal rake angle, the uncut chip thickness
is 0.2 mm. The chip thickness fluctuates between
0.25 mm and 0.4 mm. The ratio of the maximum
shear angle to the minimum shear angle during
machining is
In an orthogonal machining with a tool of 9 degree orthogonal rake angle, the uncut chip thickness is 0.2mm.
The chip thickness fluctuates between 0.25 mm and 0.4 mm. The ratio of the maximum shear angle to the
minimum shear angle during machining is
Chapter 23 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 23 - Describe the types of machining operations that...Ch. 23 - What is turning? What kind of chips are produced...Ch. 23 - What is the thrust force in turning? What is the...Ch. 23 - What are the components of a lathe?Ch. 23 - (a) What is a tracer lathe? (b) What is an...Ch. 23 - Describe the operations that can be performed on a...Ch. 23 - Why were power chucks developed?Ch. 23 - Explain why operations such as boring on a lathe...Ch. 23 - Why are turret lathes typically equipped with more...Ch. 23 - Describe the differences between boring a...
Ch. 23 - How is drill life determined?Ch. 23 - What is the difference between a conventional...Ch. 23 - Why are reaming operations performed?Ch. 23 - Explain the functions of the saddle on a lathe.Ch. 23 - Describe the relative advantages of (a)...Ch. 23 - Explain how external threads are cut on a lathe.Ch. 23 - Prob. 17RQCh. 23 - Explain the reasoning behind the various design...Ch. 23 - Note that both the terms tool strength and...Ch. 23 - (a) List and explain the factors that contribute...Ch. 23 - Explain why the sequence of drilling, boring, and...Ch. 23 - Why would machining operations be necessary even...Ch. 23 - A highly oxidized and uneven round bar is being...Ch. 23 - Describe the difficulties that may be encountered...Ch. 23 - (a) Does the force or torque in drilling change as...Ch. 23 - Explain the similarities and differences in the...Ch. 23 - Describe the advantages and applications of having...Ch. 23 - Assume that you are asked to perform a boring...Ch. 23 - Explain the reasons for the major trend that has...Ch. 23 - Describe your observations concerning the contents...Ch. 23 - The footnote to Table 23.12 states that as the...Ch. 23 - In modern manufacturing, which types of metal...Ch. 23 - Sketch the tooling marks you would expect if a...Ch. 23 - What concerns would you have in turning a powder...Ch. 23 - The operational severity for reaming is much lower...Ch. 23 - Review Fig. 23.6, and comment on the factors...Ch. 23 - Explain how gun drills remain centered during...Ch. 23 - Comment on the magnitude of the wedge angle on the...Ch. 23 - If inserts are used in a drill bit (see Fig....Ch. 23 - Refer to Fig. 23.11b, and in addition to the tools...Ch. 23 - Calculate the same quantities as in Example 23.1...Ch. 23 - Estimate the machining time required to rough turn...Ch. 23 - A high-strength cast-iron bar 8 in. in diameter is...Ch. 23 - A 0.30-in.-diameter drill is used on a drill press...Ch. 23 - In Example 23.4, assume that the workpiece...Ch. 23 - For the data in Problem 23.45, calculate the power...Ch. 23 - A 6-in.-diameter aluminum cylinder 10 in. in...Ch. 23 - A lathe is set up to machine a taper on a bar...Ch. 23 - Assuming that the coefficient of friction is 0.25,...Ch. 23 - A 3-in.-diameter, gray cast iron cylindrical part...Ch. 23 - Would you consider the machining processes...Ch. 23 - Would it be difficult to use the machining...Ch. 23 - If a bolt breaks in a hole, it typically is...Ch. 23 - An important trend in machining operations is the...Ch. 23 - Review Fig. 23.8d, and explain if it would be...Ch. 23 - Boring bars can be designed with internal damping...Ch. 23 - A large bolt is to be produced from extruded...Ch. 23 - Make a comprehensive table of the process...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- In orthogonal machining operation the chip thickness and the uncut chip thickness are equal to 0.45 mm. If the tool rake and is 0 deg. What is the shear plane angle?arrow_forwardElectroforming is an example of secondary machining process. Select one: True Falsearrow_forwardIn an orthogonal machining with a tool of gº orthogonal rake angle, the uncut chip thickness is 0.2 mm. The chip thickness fluctuates between 0.25 mm and 0 4 mm what is the ratio of the maximum shear angle to the minimum shear angle during machining?arrow_forward
- i need the answer quicklyarrow_forwardThe following data is given for slab milling of a 300 mm long 50 mm wide mild steel block: Cutter of diameter= 60 mm; Numbers of teeth =12; Cutter speed = 120 rev/min; Depth of cut = 3.2 mm; Feed is 0.25 mm/tooth.Determine (i) Table feed in mm/min, (ii) MRR (iii) Power (iv) Torque and (v) Total machining time. Assumesuitable approach and over-run and specific energy of mild steel as 5 Ws/mm3.arrow_forwardA single-point cutting tool with 12° rake angle is used to machine a steel work-piece. The depth of cut, i.e. uncut thickness is 0.81 mm. The chip thickness under orthogonal machining condition is 1.8 mm. What is the shear angle.arrow_forward
- A face milling operation is used to machine 6.0 mm from the top surface of a rectangular piece of aluminum 300 mm long by 125 mm wide in a single pass. The cutter follows a path that is centered over the workpiece. It has four teeth and is 150 mm in diameter. Cutting speed = 2.8 m/s, and chip load = 0.27 mm/tooth. Determine (a) the actual machining time to make the pass across the surface and (b) the maximum metal removal rate during cuttingarrow_forwardUsing slot milling with a cutting tool surface width of 36mm was performed from the top surface to cut a workpiece of 85 x 42 x 8 cm into two equal parts. The milling cutter is 180 mm in diameter and has eight teeth. Cutting speed = 60 m/min, chip load = 0.35 mm/ tooth, and depth of cut = 2 mm, given that the setup and machine settings provide an approach distance of 7mm before actual cutting begins and an overtravel distance of 20 mm after actual cutting has finished, and the return time is a 4-second for idle pass stroke. Determine:- 1. What is the total machining time required for the entire workpiece? 2. The maximum metal removal rate during cutting.arrow_forwardNonearrow_forward
- Question 2 Briefly explain the following chips formation in machining operation with the help of figure: (a) Continuous (b) Discontinuous (c) Built-up edgearrow_forwardCalculate the machining time required for making 60 holes on an MS plate of 80 mm thickness with a drillbit of diameter 20 mm with a cutting speed V= 40 m/min, the feed f = 0.2 mm/rev. (Assume approach length,A and over run O as 2mm and point angle as 110o). Calculate material removal rate.arrow_forwarda. Give 3 reasons why conventional machining is essential. b. What is the difference between the primary shear zone and secondary shear zone? c. Name a device or procedure used to measure cutting temperature Please type the answers!!arrow_forward
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