Physics for Scientists and Engineers, Vol. 1
Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
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Chapter 23, Problem 27P

(a)

To determine

The electric potential at the point on y -axis at y=3.00m if q1=q2=q3=+2μC .

(a)

Expert Solution
Check Mark

Answer to Problem 27P

The electric potential at the point on y -axis at y=3.00m if q1=q2=q3=+2μC is 12.9kV .

Explanation of Solution

Given:

The charge on each particle is q=2.00μC

Formula used:

The expression for the potential at the point whose coordinates is (0,3) ,

  V=kqr1+kqr2+kqr3=kq(1 r 1 +1 r 2 +1 r 3 )

Calculation:

  Physics for Scientists and Engineers, Vol. 1, Chapter 23, Problem 27P

Figure (1)

The distance to the point P from the charge q1 is r1=3m

The distance to the point P from the charge q2 is,

  r2= ( 3m )2+ ( 3m )2=4.243m

The distance to the point P from the charge q3 is,

  r3= ( 3m )2+ ( 6m )2=6.71m

The potential at the point is calculated as,

  V=kq(1 r 1 +1 r 2 +1 r 3 )=(8.988× 109 Nm 2/ C 2)×(2μC)×(1 3m+1 4.243m+1 6.71m)=12.9kV

Conclusion:

Therefore, the electric potential at the point on y -axis at y=3.00m if q1=q2=q3=+2μC is 12.9kV .

(b)

To determine

The electric potential at the point on y -axis at y=3.00m if q1=q2=+2μC and q3=2.00μC .

(b)

Expert Solution
Check Mark

Answer to Problem 27P

The electric potential at the point on y -axis at y=3.00m if q1=q2=+2μC and q3=2.00μC is 7.55kV .

Explanation of Solution

Given:

The charge on first and second particle is q1=q2=+2.00μC

The charge on third particle is q3=2.00μC

Formula used:

The expression for the potential at the point whose coordinates is (0,3) ,

  V=kqr1+kqr2+kqr3=k( q 1 r 1 + q 2 r 2 + q 3 r 3 )

Calculation:

The distance to the point P from the charge q1 is r1=3m

The distance to the point P from the charge q2 is,

  r2= ( 3m )2+ ( 3m )2=4.243m

The distance to the point P from the charge q3 is,

  r3= ( 3m )2+ ( 6m )2=6.71m

The potential at the point is calculated as,

  V=k( q 1 r 1 + q 2 r 2 + q 3 r 3 )=(8.988× 109 Nm 2/ C 2)×[2μC3m+2μC4.243m+( 2μC)6.71m]=7.55kV

Conclusion:

Therefore, the electric potential at the point on y -axis at y=3.00m if q1=q2=+2μC and q3=2.00μC is 7.55kV .

(c)

To determine

The electric potential at the point on y -axis at y=3.00m if q1=q2=+2μC and q3=2.00μC .

(c)

Expert Solution
Check Mark

Answer to Problem 27P

The electric potential at the point on y -axis at y=3.00m if q1=q3=+2μC and q2=2.00μC is 4.43kV .

Explanation of Solution

Given:

The charge on first and third particle is q1=q3=+2.00μC

The charge on second particle is q2=2.00μC

Formula used:

The expression for the potential at the point whose coordinates is (0,3) ,

  V=kqr1+kqr2+kqr3=k( q 1 r 1 + q 2 r 2 + q 3 r 3 )

Calculation:

The distance to the point P from the charge q1 is r1=3m

The distance to the point P from the charge q2 is,

  r2= ( 3m )2+ ( 3m )2=4.243m

The distance to the point P from the charge q3 is,

  r3= ( 3m )2+ ( 6m )2=6.71m

The potential at the point is calculated as,

  V=k( q 1 r 1 + q 2 r 2 + q 3 r 3 )=(8.988× 109 Nm 2/ C 2)×[2μC3m+2μC4.243m+( 2μC)6.71m]=4.43kV

Conclusion:

Therefore, The electric potential at the point on y -axis at y=3.00m if q1=q3=+2μC and q2=2.00μC is 4.43kV .

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Chapter 23 Solutions

Physics for Scientists and Engineers, Vol. 1

Ch. 23 - Prob. 11PCh. 23 - Prob. 12PCh. 23 - Prob. 13PCh. 23 - Prob. 14PCh. 23 - Prob. 15PCh. 23 - Prob. 16PCh. 23 - Prob. 17PCh. 23 - Prob. 18PCh. 23 - Prob. 19PCh. 23 - Prob. 20PCh. 23 - Prob. 21PCh. 23 - Prob. 22PCh. 23 - Prob. 23PCh. 23 - Prob. 24PCh. 23 - Prob. 25PCh. 23 - Prob. 26PCh. 23 - Prob. 27PCh. 23 - Prob. 28PCh. 23 - Prob. 29PCh. 23 - Prob. 30PCh. 23 - Prob. 31PCh. 23 - Prob. 32PCh. 23 - Prob. 33PCh. 23 - Prob. 34PCh. 23 - Prob. 35PCh. 23 - Prob. 36PCh. 23 - Prob. 37PCh. 23 - Prob. 38PCh. 23 - Prob. 39PCh. 23 - Prob. 40PCh. 23 - Prob. 41PCh. 23 - Prob. 42PCh. 23 - Prob. 43PCh. 23 - Prob. 44PCh. 23 - Prob. 45PCh. 23 - Prob. 46PCh. 23 - Prob. 47PCh. 23 - Prob. 48PCh. 23 - Prob. 49PCh. 23 - Prob. 50PCh. 23 - Prob. 51PCh. 23 - Prob. 52PCh. 23 - Prob. 53PCh. 23 - Prob. 54PCh. 23 - Prob. 55PCh. 23 - Prob. 56PCh. 23 - Prob. 57PCh. 23 - Prob. 58PCh. 23 - Prob. 59PCh. 23 - Prob. 60PCh. 23 - Prob. 61PCh. 23 - Prob. 62PCh. 23 - Prob. 63PCh. 23 - Prob. 64PCh. 23 - Prob. 65PCh. 23 - Prob. 66PCh. 23 - Prob. 67PCh. 23 - Prob. 68PCh. 23 - Prob. 69PCh. 23 - Prob. 70PCh. 23 - Prob. 71PCh. 23 - Prob. 72PCh. 23 - Prob. 73PCh. 23 - Prob. 74PCh. 23 - Prob. 75PCh. 23 - Prob. 76PCh. 23 - Prob. 77PCh. 23 - Prob. 78PCh. 23 - Prob. 79PCh. 23 - Prob. 80PCh. 23 - Prob. 81PCh. 23 - Prob. 82PCh. 23 - Prob. 83PCh. 23 - Prob. 84PCh. 23 - Prob. 85PCh. 23 - Prob. 86PCh. 23 - Prob. 87PCh. 23 - Prob. 88PCh. 23 - Prob. 89PCh. 23 - Prob. 90PCh. 23 - Prob. 91PCh. 23 - Prob. 92PCh. 23 - Prob. 93PCh. 23 - Prob. 94P
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