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(a)
Interpretation:
IUPAC name for the given compound has to be given.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of
Root word represents the longest continuous carbon skeleton of the organic molecule.
If the compound has an unsaturated bond present in it, then the position of the unsaturated bond is mentioned in the IUPAC name itself.
(b)
Interpretation:
IUPAC name for the given compound has to be given.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
If the compound has an unsaturated bond present in it, then the position of the unsaturated bond is mentioned in the IUPAC name itself.
(c)
Interpretation:
IUPAC name for the given compound has to be given.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
If the compound has an unsaturated bond present in it, then the position of the unsaturated bond is mentioned in the IUPAC name itself.
(d)
Interpretation:
IUPAC name for the given compound has to be given.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
If the compound has an unsaturated bond present in it, then the position of the unsaturated bond is mentioned in the IUPAC name itself.
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Chapter 23 Solutions
Bundle: General Chemistry, Loose-leaf Version, 11th + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card
- Please correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward(a) The following synthesis of the molecule shown in the circle has a major problem. What is this problem? (2 pts) 1) HBr (no peroxides) 2) H- NaNH2 Br 3) NaNH, 4) CH3Br 5) H2, Pd (b) Starting with the molecule shown below and any other materials with two carbons or less, write out an alternate synthesis of the circled molecule. More than one step is needed. Indicate the reagent(s) and the major product in all the steps in your synthesis. (5 pts) 2024 Fall Term (1) Organic Chemistry 1 (Lec) CHEM 22204 02[6386] (Hunter College) (c) Using the same starting material as in part (b) and any other materials win two carpons or less, write out syntheses of the circled molecules shown below. More than one step is needed in each case. Indicate the reagent(s) and the major product in all the steps in your synthesis. You may use reactions and products from your synthesis in part (b). (5 pts)arrow_forward
- alt ons for Free Response Questions FRQ 1: 0/5 To spectrophotometrically determine the mass percent of cobalt in an ore containing cobalt and some inert materials, solutions with known [Co?) are prepared and absorbance of each of the solutions is measured at the wavelength of optimum absorbance. The data are used to create a calibration plot, shown below. 0.90- 0.80- 0.70 0.60 0.50 0.40- 0.30 0.20- 0.10- 0.00- 0.005 0.010 Concentration (M) 0.015 A 0.630 g sample of the ore is completely dissolved in concentrated HNO3(aq). The mixture is diluted with water to a final volume of 50.00 ml. Assume that all the cobalt in the ore sample is converted to Co2+(aq). a. What is the [Co2] in the solution if the absorbance of a sample of the solution is 0.74? 13 ✗ b. Calculate the number of moles of Co2+(aq) in the 50.00 mL solution. 0.008 mols Coarrow_forwardPlease correct answer and don't used hand raitingarrow_forwardCloso-boranes and arachno-boranes are structures that exhibit B-B, B-H-B, and B-H bonds. Correct?arrow_forward
- Indicate why boron hydrides cannot form large linear or planar structures.arrow_forwardNido-boranes are structures with the molecular formula BnHn+4 that exhibit B-B, B-H-B and B-H bonds. Correct?arrow_forward8:07 AM Wed Dec 18 Final Exam 2024 copy Home Insert Draw Page Layout Formulas Data Review AA 田 General A G fx Alexis Cozort ☑ ⚫ 61% A B D E F H K M N P R S T U 3+ 10 125 mM that yielded peak heights of Aa = 9 1-(a)A sample solution was examined under XRF to quantify the analyte Ce³+. Find the response factor F, when standardized concentration of analyte [Ce³+]A = concentration of internal standard S i.e. [In³*]s = 151 mM was spiked with standardized 1600 and As = 3015 respectively? 11 12 (i)Define F, F = Aa As [A] [S] + X 13 (*Define with variables) 4000 14 15 (ii)Calculate F, F = numeral (You will use the F value in part 1-(b) below) As 16 (*Calculate with numerals) 17 18 1-(b)To determine the unknown conc of analyte [Ce³+], a volume of 15 mL of internal standard S having a concentration [In³+]s = 0.264 M 19 20 was added to 45 mL of unknown, and the mixture was diluted to 100 mL in a volumetric flask. XRF analysis yielded a spectrum, Figure-1, where peak heights A and As are…arrow_forward
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