Quantitative Chemical Analysis
Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
Question
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Chapter 23, Problem 23.51P

(a)

Interpretation Introduction

Interpretation:

The value of adjusted retention time and retention factors for pentafluorobenzene and benzene has to be calculated.

Concept introduction:

Retention factor:

The retention factor (k) is given by

k=tr-tmtmWhere,k-retentionfactortr-timerequiredtoelutethepeaktm-timerequiredformobilephasetopassthroughthecolumn.

(a)

Expert Solution
Check Mark

Answer to Problem 23.51P

  • The value of adjusted retention time for pentafluorobenzene is 11.92min.
  • The value of retention factor for pentafluorobenzene is 11.25.
  • The value of adjusted retention time for benzene is 12.14min.
  • The value of retention factor for benzene is 11.45.

Explanation of Solution

Given information,

Elutiontimeforunretainedsoluteis1.06min.Lengthofthecolumnis30.0manddiameteris0.530mm.Thicknessofthestationaryphaseontheinnerwallis3.0µm.

Calculate the value of adjusted retention time and retention factor for pentafluorobenzene

tr'=12.98-1.06=11.92min.k=11.921.06=11.25

Calculate the value of adjusted retention time and retention factor for benzene

tr'=13.20-1.06=12.14min.k=12.141.06=11.45

(b)

Interpretation Introduction

Interpretation:

The value of relative retention (α) has to be calculated.

(b)

Expert Solution
Check Mark

Answer to Problem 23.51P

  • The value of relative retention (α) is 1.018.

Explanation of Solution

Given information,

tr'valueofbenzeneis12.14min.tr'valueofpentafluorobenzeneis11.92min.

Calculate the value of relative retention (α)

α=12.1411.92=1.018.

The value of relative retention (α) is 1.018.

(c)

Interpretation Introduction

Interpretation:

The number of plates (N) and plate height has to be calculated.

Concept introduction:

Plates of column:

The relationship between Nandw1/2

N=5.55tr2w1/22Where,N-numberofplatesoncolumntr-retentiontimew1/2-half-width

(c)

Expert Solution
Check Mark

Answer to Problem 23.51P

  • The number of plates for pentafluorobenzene is 6.08×104.
  • The plate height for pentafluorobenzene is 0.493mm.
  • The number of plates for benzene is 6.60×104.
  • The plate height for benzene is 0.455mm.

Explanation of Solution

Given information,

w1/2(C6HF5)=0.124min.w1/2(C6H6)=0.121min.Columnlength=30.0m.

Calculate the number of plates and plate height for C6HF5

N=5.55tr2w1/22=5.55(12.98)2(0.124)2=6.08×104plates.Plateheight(H)=LN=30.0m6.08×104=0.493mm.

Calculate the number of plates and plate height for C6H6

N=5.55tr2w1/22=5.55(13.20)2(0.121)2=6.60×104plates.Plateheight(H)=LN=30.0m6.60×104=0.455mm.

(d)

Interpretation Introduction

Interpretation:

The number of plates has to be calculated by using the value of width.

Concept introduction:

Plates of column:

The relationship between Nandw

N=16tr2w2Where,N-numberofplatesoncolumntr-retentiontimew-half-width

(d)

Expert Solution
Check Mark

Answer to Problem 23.51P

  • The number of plates for pentafluorobenzene is 5.57×104.
  • The number of plates for benzene is 4.88×104.

Explanation of Solution

Given information,

wfor(C6HF5)=0.220min.wfor(C6H6)=0.239min.

Calculate the number of plates for C6HF5

N=16tr2w2=5.55(12.98)2(0.220)2=5.57×104plates.

Calculate the number of plates for C6H6

N=16tr2w2=16(13.20)2(0.239)2=4.88×104plates.

(e)

Interpretation Introduction

Interpretation:

The resolution between the given two peaks has to be calculated.

(e)

Expert Solution
Check Mark

Answer to Problem 23.51P

  • The resolution between the given two peaks is 0.96.

Explanation of Solution

Given information,

ValueofΔtr=13.20-12.98=0.22Valueofwavis0.229.

Calculate the resolution between the given two peaks

Resolution=Δtrwav=13.20-12.980.229=0.96

The resolution between the given two peaks is 0.96.

(f)

Interpretation Introduction

Interpretation:

The numerical value of resolution has to be calculated.

(f)

Expert Solution
Check Mark

Answer to Problem 23.51P

  • The numerical value of resolution is 0.97.

Explanation of Solution

Given information,

N1=5.57×104plates.N2=4.88×104plates.

Calculate the number of plates

N=N1N2=(5.57×104)(4.88×104)=2718160000=5.21×104plates.

Calculate the resolution

Resolution=N4(γ-1)=5.21×1044(1.017-1)=0.97.

The resolution is 0.97.

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