Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
9th Edition
ISBN: 9781305968707
Author: Spencer L. Seager
Publisher: Brooks Cole
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Question
Chapter 23, Problem 23.19E
Interpretation Introduction
Interpretation:
The way by which the formation of lactate allows glycolysis to continue under anaerobic conditions is to be explained.
Concept introduction:
Lactate is the conjugate base of lactic acid. Lactic acid is the organic acid that is soluble in water. It is produced under the anaerobic condition. The high amount of lactate in blood indicates the lack of oxygen.
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Chapter 23 Solutions
Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
Ch. 23 - Why is glucose considered the pivotal compound in...Ch. 23 - Prob. 23.2ECh. 23 - Prob. 23.3ECh. 23 - Describe what is meant by the terms blood sugar...Ch. 23 - What range of concentrations for glucose in blood...Ch. 23 - Prob. 23.6ECh. 23 - Prob. 23.7ECh. 23 - Prob. 23.8ECh. 23 - Prob. 23.9ECh. 23 - Prob. 23.10E
Ch. 23 - Prob. 23.11ECh. 23 - Prob. 23.12ECh. 23 - Prob. 23.13ECh. 23 - Prob. 23.14ECh. 23 - Prob. 23.15ECh. 23 - Prob. 23.16ECh. 23 - Prob. 23.17ECh. 23 - Prob. 23.18ECh. 23 - Prob. 23.19ECh. 23 - Prob. 23.20ECh. 23 - Prob. 23.21ECh. 23 - Prob. 23.22ECh. 23 - Prob. 23.23ECh. 23 - Prob. 23.24ECh. 23 - Prob. 23.25ECh. 23 - Prob. 23.26ECh. 23 - Prob. 23.27ECh. 23 - Prob. 23.28ECh. 23 - Prob. 23.29ECh. 23 - Prob. 23.30ECh. 23 - Prob. 23.31ECh. 23 - Prob. 23.32ECh. 23 - Prob. 23.33ECh. 23 - Prob. 23.34ECh. 23 - Prob. 23.35ECh. 23 - Prob. 23.36ECh. 23 - Prob. 23.37ECh. 23 - Prob. 23.38ECh. 23 - Prob. 23.39ECh. 23 - Prob. 23.40ECh. 23 - Prob. 23.41ECh. 23 - Prob. 23.42ECh. 23 - Prob. 23.43ECh. 23 - Prob. 23.44ECh. 23 - Prob. 23.45ECh. 23 - Prob. 23.46ECh. 23 - Prob. 23.47ECh. 23 - Prob. 23.48ECh. 23 - Prob. 23.49ECh. 23 - Prob. 23.50ECh. 23 - Prob. 23.51ECh. 23 - Prob. 23.52ECh. 23 - Prob. 23.53ECh. 23 - Prob. 23.54ECh. 23 - Prob. 23.55ECh. 23 - Prob. 23.56ECh. 23 - Prob. 23.57ECh. 23 - Prob. 23.58ECh. 23 - Prob. 23.59ECh. 23 - Prob. 23.60ECh. 23 - Prob. 23.61ECh. 23 - Prob. 23.62ECh. 23 - Prob. 23.63ECh. 23 - Prob. 23.64ECh. 23 - Prob. 23.65ECh. 23 - Lactate dehydrogenase catalyzes the following...Ch. 23 - Prob. 23.67ECh. 23 - Prob. 23.68ECh. 23 - Prob. 23.69ECh. 23 - Prob. 23.70ECh. 23 - A friend started to make wine by adding yeast to...Ch. 23 - Prob. 23.72ECh. 23 - Explain why monitoring blood lactate levels might...Ch. 23 - Prob. 23.74ECh. 23 - Prob. 23.75ECh. 23 - Prob. 23.76ECh. 23 - Prob. 23.77ECh. 23 - Prob. 23.78ECh. 23 - Prob. 23.79ECh. 23 - Prob. 23.80ECh. 23 - Prob. 23.81ECh. 23 - Prob. 23.82ECh. 23 - Prob. 23.83ECh. 23 - Prob. 23.84ECh. 23 - Prob. 23.85ECh. 23 - Prob. 23.86ECh. 23 - Prob. 23.87ECh. 23 - Prob. 23.88ECh. 23 - Prob. 23.89ECh. 23 - Prob. 23.90E
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- What range of concentrations for glucose in blood is considered a normal fasting level?arrow_forwardExplain why monitoring blood lactate levels might be a useful technique to gauge the amount of conditioning in an Olympic runner.arrow_forwardTrypanosomes living in the bloodstream obtain all their free energy from glycolysis. They take up glucose from the host’s blood and excrete pyruvate as a waste product. In this part of their life cycle, trypanosomes do not carry out any oxidative phosphorylation, but they do use another oxygen-dependent pathway, which is absent in mammals, to oxidize NADH. Would this pathway be necessary if the trypanosome excreted lactate rather than pyruvate? Explain.arrow_forward
- 2. Why do enzymes become inactive at very low temperature? Why do enzymes become inactive at very high temperatures? (Hint: It is NOT the same reason.)arrow_forwardExplain the inputs and outputs of glycolysis, fermentation and the Krebs cycle, and state how many enzymes are involved in each process.arrow_forwardFind out the role and chemical reactions of the following reagents in the blood glucose level determination by glucose oxidase method. a) Sodium sulphate – Zinc sulphate solution b ) Glucose oxidase reagent c) Peroxidasearrow_forward
- Describe the energy output, initial substrates, and end products of the glycolysis process.arrow_forwardAnaerobic glycolysis (i.e., lactic acid fermentation) produces pyruvate that is then converted to lactate through the activity of lactate dehydrogenase. The conversion of pyruvate to lactate would seem to be an unnecessary step, since this process does not result in any further release of energy. Explain the necessity for the production of lactate as the endpoint for anaerobic glycolysis.arrow_forwardDescribeenergy consumed vs released in reactions. Differentiate between endergonic vs exergonic reactions, anabolism vs catabolism, and coupled reactions.arrow_forward
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